Question

我必须从我的本地Visual Studio 2013项目结构中读出一个XML文件（已经存在的内容），而不是从harddrive目录中读出（如大多数教程/指南中所述，我已经阅读了最后2个小时......）在读出过程之后，我必须在其中搜索一些标记名称。

我必须这样做，因为要求是，指定的本地XML文件不应该出现在输出目录中的构建过程之后......

那我怎么能这样做呢？

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这是我的AccessData.xml文件（在项目目录中：＆＃34; LinqToXML_Example / AccessData.xml＆＃34;）：

<?xml version="1.0" encoding="utf-8"?>

  <Clients>


    <Client>

        <Username>Administrator</Username>

        <Password>Admin-Password</Password>

        <Settings>
          <Item1>Admin-Setting 1</Item1>
          <Item2>Admin-Setting 2</Item2>
          <Item3>Admin-Setting 3</Item3>
        </Settings>

    </Client>



    <Client>

        <Username>Service</Username>

        <Password>Srv-Password</Password>

        <Settings>
          <Item1>Srv-Setting 1</Item1>
          <Item2>Srv-Setting 2</Item2>
          <Item3>Srv-Setting 3</Item3>
        </Settings>

    </Client>



    <Client>

        <Username>Customer</Username>

        <Password>Cust-Password</Password>

        <Settings>
          <Item1>Cust-Setting 1</Item1>
          <Item2>Cust-Setting 2</Item2>
          <Item3>Cust-Setting 3</Item3>
        </Settings>

    </Client>


  </Clients>

这是我的Program.cs文件：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Xml;
using System.Xml.Linq;
using System.Reflection;

namespace LinqToXML_Example
{
    public class Program
    {


        public static string SearchForUsername(string username, XElement clients)
        {

            var userName = from p in clients.Elements()
                            where p.Element("Username").Value == username
                            select p.Element("Username").Value;

            foreach (var p in userName)
            {
                return p + " found!";
            }

            return "User '" + username + "' does not exist!";
        }



        public static bool IsUsernameExisting(string username, XElement clients)
        {
            var userName = from p in clients.Elements()
                            where p.Element("Username").Value == username
                            select p.Element("Username").Value;

            foreach (var p in userName)
            {
                return true;
            }

            return false;
        }



        public static string SearchForUsernamePassword(string username, XElement clients)
        {

            if (IsUsernameExisting(username, clients))
            {
                var password = from p in clients.Elements()
                                where p.Element("Username").Value == username
                                select p.Element("Password").Value;

                foreach (var p in password)
                    return "The password of client " + username + " is: " + p;
            }

            return "Cannot get the username's password, because of a wrong Username!";
        }



        public static List<string> ReadUserSettings(string username, XElement clients)
        {

            List<string> settingsList = new List<string>();


            if (IsUsernameExisting(username, clients))
            {
                var setting = from s in clients.Elements()
                                where s.Element("Username").Value == username
                                select s.Element("Settings");

                foreach (var p in setting)
                {
                    settingsList.Add(p.Element("Item1").Value);
                    settingsList.Add(p.Element("Item2").Value);
                    settingsList.Add(p.Element("Item3").Value);
                }

                return settingsList;
            }


            var errorMsg = "Cannot get the username's settings, because of a wrong Username!";
            settingsList.Add(errorMsg);

            return settingsList;
        }





        public static void Query(string username, XElement clients)
        {
            // Search for specific Username:
            Console.WriteLine("Search for Client " + "'" + username + "' (based on Usernames):");

            string result = SearchForUsername(username, clients);
            Console.WriteLine(result);


            Console.WriteLine("");


            // Search for Password of Client:
            Console.WriteLine("Search for Password of Client " + "'" + username + "':");

            result = SearchForUsernamePassword(username, clients);
            Console.WriteLine(result);


            Console.WriteLine("");


            // Readout the Settings of Client:
            Console.WriteLine("Readout the Settings of Client " + "'" + username + "':");

            List<string> resultList = new List<string>();
            resultList = ReadUserSettings(username, clients);

            if (resultList.Count != 1)
            {
                for (int i = 0; i < resultList.Count(); i++)
                {
                    var itemcounter = i + 1;
                    Console.WriteLine("Item" + itemcounter + ": " + resultList.ElementAt(i));
                }
            }

            else Console.WriteLine(resultList.ElementAt(0));



            Console.Read();
        }




        static void Main()
        {

            var asm = Assembly.GetExecutingAssembly();

  // Bug fix: "AccessData.xml" has to be changed to: "LinqToXML_Example.AccessData.xml" 
            var textStream = asm.GetManifestResourceStream("AccessData.xml");

       // Bug fix: Has to be changed to: var xmlReader = new XmlTextReader(textStream);
            var xmlReader = new XmlReader(textStream);

            XElement clients = XElement.Load(xmlReader);

            Query("Administrator", clients);
        }
    }
}

我已将AccessData.xml文件的属性更改为：

Build Action = "Resource" // Bug fix: Has to be changed to: 'Embeded Resource'

Copy to output directory = "Never"

不幸的是我无法访问我的xml文件:(（

Answer 1

大致扫描了您的代码，以下行似乎是问题所在：

var textStream = asm.GetManifestResourceStream("AccessData.xml");

默认情况下，资源名称以项目的默认命名空间为前缀。此外，包含该文件的项目文件夹也包含在名称中。因此，在您的情况下，资源名称可能是＆＃34; LinqToXML_Example.AccessData.xml＆＃34; 而不是＆＃34; AccessData.xml＆＃34;。

此外，您应该将构建操作设置为嵌入式资源。

如果要查找项目文件中包含的所有资源名称，可以使用此代码并在调试时检查返回值：

string[] names = asm.GetManifestResourceNames();

有关详细信息，请参阅此link。

读出XML文件（仅来自项目）

1 个答案: