Question

我正在尝试编写一个PHP程序来计算某个日期的年，月和日数，并在我尝试获得结果时收到错误：

致命错误：在写上下文中不能使用函数返回值

此行显示错误：

$values($years, $months, $days) = $c->difference($diff);

完整的代码是：

<?php

    class Calculator {

        public $diff = NULL;

        public function calculate ($birthday) {
            $date = date('m/d/y', time());
            $diff = abs(strtotime($date) - strtotime($birthday));
            return $diff;
        }

        public function difference ($diff) {
            $years = floor($diff / (365*60*60*24));
            $months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
            $days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
            return array($years, $months, $days);
        }

    }


    $c = new Calculator;
    $diff = $c->calculate("11/13/1995");
    $values($years, $months, $days) = $c->difference($diff);
    echo $values[0] . " years, " . $values[1] . " months, " . $values[2] . " days.";

?>

为什么我收到此错误？

Answer 1

您需要使用list()：

$values($years, $months, $days) = $c->difference($diff);

应该是：

list($years, $months, $days) = $c->difference($diff);

或者使用当前的回声，只需分配给数组$values：

$values = $c->difference($diff);

看起来你正在尝试两者的混合。

Answer 2

简单地

$values = $c->difference($diff);

值将保存返回的数组。

致命错误：在写上下文中不能使用函数返回值

2 个答案: