当我在SortedList上使用.net BinarySearch时,如果我在同一个列表上使用我自己的自制二进制搜索方法,它会花费更长的时间吗?
使用.net binarysearch:
int ipos = MyList.Keys.ToList().BinarySearch(unSearchFor);
if (ipos >= 0)
{
// exact target found at position "ipos"
return MyList[unSearchFor];
}
else
{
// Exact key not found:
// BinarySearch returns negative when the exact target is not found,
// which is the bitwise complement of the next index in the list larger than the target.
ipos = ~ipos;
try
{
return MyList.Values[ipos - 1];
}
catch
{
return null;
}
}
我的二元搜索方法:
int nStart = 0;
int nEnd = MyList.Count - 1;
int mid = 0;
while (nStart <= nEnd)
{
mid = nStart + (nEnd - nStart) / 2;
uint unCurrKey = MyList.Values[mid].Key;
if (unSearchFor == unCurrKey)
return MyList.Values[mid];
if (unSearchFor < unCurrKey)
{
nEnd = mid - 1;
}
else
{
nStart = mid + 1;
}
}
答案 0 :(得分:7)
不是因为你在下面的列表中调用BinarySearch()时你正在做.ToList()吗?
MyList.Keys.ToList().BinarySearch(unSearchFor);