Question

我有以下XML文档。

<case.considered>
    <case.ref BVtable="yes">
        <citetitle type="case" full="Lee Ting Lam v Leung Kam Ming" legtype="ord">Lee Ting Lam v Leung Kam Ming</citetitle>
        <citecitation full="[1980] HKLR 657">[1980] HKLR 657</citecitation>
    </case.ref>
</case.considered>
<case.considered>
    <case.ref BVtable="yes">
        <citetitle type="case" full="Chan Pui Ki v Leung On" legtype="ord">Chan Pui Ki v Leung On</citetitle>
        <citecitation full="[1996] 2 HKLR 401, [1996] 2 HKC 565">[1996] 2 HKLR 401</citecitation>
    </case.ref>
</case.considered>
<case.considered>
    <case.ref BVtable="yes" annotation="considered">
        <citetitle type="case" full="Sung Fuk Wah v Lam Wai Leuk" legtype="ord">Sung Fuk Wah v Lam Wai Leuk</citetitle>
        <citecitation full="(unrep., HCA 3676/1994, [1995] HKLY 527)">(unrep., HCA 3676/1994)</citecitation>
    </case.ref>
</case.considered>
<case.considered>
    <case.ref BVtable="yes" annotation="distinguished">
        <citetitle type="case" full="Blamire v South Cumbria Health Authority" legtype="ord">Blamire v South Cumbria Health Authority</citetitle>
        <citecitation full="[1993] PIQR Q1">[1993] PIQR Q1</citecitation>
    </case.ref>
</case.considered>
<case.considered>
    <case.ref BVtable="yes" annotation="distinguished">
        <citetitle type="case" full="W (A child) v Hammersmith Hospitals NHS Trust" legtype="ord">W (A child) v Hammersmith Hospitals NHS Trust</citetitle>
        <citecitation full="[2002] 3 QR 5, [2002] All ER (D) 397">[2002] All ER (D) 397</citecitation>
    </case.ref>
</case.considered>

以及下面的XSLT

    <xsl:template match="ref.group" name="ref.group">
        <xsl:if test="leg.mentioned">
            <xsl:for-each select="./leg.ref">
                <xsl:if test="./@considered='no'">
                    <div class="section-sect1">
                        <xsl:text>Legislation mentioned in the judgment</xsl:text>
                    </div>
                    <div class="para">
                        <xsl:value-of select="citetitle"/>
                        <xsl:text>, </xsl:text>
                        <xsl:for-each select="./leg.ptr.group/leg.ptr">
                            <xsl:value-of select="."/>
                            <xsl:if test="not(position() = last())">
                                <xsl:text disable-output-escaping="yes">, </xsl:text>
                            </xsl:if>
                        </xsl:for-each>
                    </div>
                </xsl:if>
            </xsl:for-each>
        </xsl:if>
        <xsl:if test="//case.considered">
            <div class="section-sect1">
                <xsl:text>Case cited in the judgment</xsl:text>
            </div>
            <xsl:apply-templates select="//case.considered" mode="x"/>
        </xsl:if>
        <xsl:if test="./other.mentioned">
            <div class="section-sect1">
                <xsl:text>Other materials mentioned in the judgment</xsl:text>
            </div>
            <xsl:apply-templates select="./other.mentioned"/>
        </xsl:if>
        <xsl:apply-templates select="//judgment"/>
    </xsl:template>


  <xsl:template match="case.considered" mode="x">
        <div class="para">
            <xsl:apply-templates select="case.ref" mode="x"/>
        </div>
    </xsl:template>

    <xsl:template match="case.ref" mode="x">

        <span class="font-style-italic">
            <xsl:value-of select="./citetitle[@full]"/>
        </span>
        <xsl:text> </xsl:text>
        <xsl:value-of select="./citecitation/@full"/>
    </xsl:template>

这里我无法知道如何根据citetitle

中的文字对数据进行排序

请告诉我如何对数据进行排序。

由于

Answer 1

我猜你要添加排序是 case.considered 。目前，你正在这样做

<xsl:apply-templates select="//case.considered" mode="x"/>

要进行排序，您需要将其更改为

<xsl:apply-templates select="//case.considered" mode="x">
    <xsl:sort select="case.ref/citetitle" />
</xsl:apply-templates>

这假设每个 case.considered 元素只有一个 case.ref 元素。如果有多个，则在排序中仅使用第一个。

基于字母顺序排序

1 个答案: