如何在处理时弹出消息 - python

Question

我想知道，如何在处理/执行程序/功能时弹出消息。我的意思是，

def Select():
    path=tkFileDialog.askopenfilename(filetypes=[("Image File",'.jpg')])
    im = skimage.io.imread(path, as_grey=True)
    im = skimage.img_as_ubyte(im)
    im /= 32
    g = skimage.feature.greycomatrix(im, [1], [0], levels=8, symmetric=False, normed=True)
    cont = skimage.feature.greycoprops(g, 'contrast')[0][0]
    cont_list1.append(cont)
    ene = skimage.feature.greycoprops(g, 'energy')[0][0]
    ene_list1.append(ene)
    homo = skimage.feature.greycoprops(g, 'homogeneity')[0][0]
    homo_list1.append(homo)
    cor = skimage.feature.greycoprops(g, 'correlation')[0][0]
    cor_list1.append(cor)
    dis = skimage.feature.greycoprops(g, 'dissimilarity')[0][0]
    dis_list1.append(dis)

我想显示一条消息，说明正在计算功能，一旦计算完毕，该消息就会消失。

但我不需要ok按钮。我不知道如何实现这一点。这些计算的结果将显示在单独的输入框中。欢迎任何建议。

Answer 1

看看这个。它打开一个包含文本的窗口，当计算完成时，文本将更改为结果。

>>> import time
>>> def processingPleaseWait(text, function):
    import Tkinter, time, threading
    window = Tkinter.Toplevel() # or tkinter.Tk()
    # code before computation starts
    label = Tkinter.Label(window, text = text)
    label.pack()
    done = []
    def call():
        result = function()
        done.append(result)

    thread = threading.Thread(target = call)
    thread.start() # start parallel computation
    while thread.is_alive():
        # code while computing
        window.update()
        time.sleep(0.001)
    # code when computation is done
    label['text'] = str(done)


>>> processingPleaseWait('waiting 2 seconds...', lambda: time.sleep(2))