Postgresql存储函数只返回不带列名的值

Question

我是Postgresql的新手。我刚刚用复合类型创建了函数。

以下是我的代码：

create type search_type as (
result_id bigint, 
result_name character varying,
result_loc character varying,
result_type character varying,
result_pic character varying
);

    CREATE OR REPLACE FUNCTION search_result("@search_text" character varying)
  RETURNS SETOF search_type AS
$BODY$
DECLARE r search_type%rowtype;
BEGIN   
    FOR r IN SELECT "User_id" AS result_id, CONCAT("User_firstname", ' ', "User_lastname") AS result_name, "User_loc" AS result_loc, "User_picurl" AS result_pic, 'user' AS result_type FROM users_list WHERE CONCAT("User_firstname", ' ', "User_lastname") LIKE CONCAT("@search_text", '%') LOOP
        RETURN NEXT r;
    END LOOP;
    FOR r IN SELECT "Community_id" AS result_id, "Community_name" AS result_name, "Community_location" AS result_loc, "Community_img_url" AS result_pic, 'community' AS result_type FROM community_list WHERE "Community_name" LIKE CONCAT("@search_text", '%') AND "Type" = 'Created' LOOP
        RETURN NEXT r;
    END LOOP;
    RETURN;
END
$BODY$
  LANGUAGE plpgsql

但是，当我像下面的代码一样调用存储的函数时，它只会使用不具有列名的数据。

SELECT search_result('c');

原因是什么？

如何使用值返回列名？

以上是recorsd返回。

但我需要得到结果：

result_id  result_name  result_loc      result_pic  result_type
---------  -----------  ----------      -----------  ----------
13         test1        San Francisco                user
14         test2        San Francisco                user
15         test3        San Francisco                user
16         test4        San Francisco                user
17         test5        San Francisco                user

如何获得上述结果？

更新

新代码：

CREATE OR REPLACE FUNCTION search_result("@search_text" character varying, "@row_start" integer, "@row_end" integer)
  RETURNS SETOF search_type AS
$BODY$
DECLARE r search_type%rowtype;
BEGIN   
    FOR r IN SELECT "User_id" AS result_id, CONCAT("User_firstname", ' ', "User_lastname") AS result_name, "User_loc" AS result_loc, "User_picurl" AS result_pic, 'user' AS result_type FROM users_list WHERE CONCAT("User_firstname", ' ', "User_lastname") LIKE CONCAT("@search_text", '%') ORDER BY CONCAT("User_firstname", ' ', "User_lastname") ASC LIMIT "@row_end" OFFSET "@row_start" LOOP
        RETURN NEXT r;
    END LOOP;
    FOR r IN SELECT "Community_id" AS result_id, "Community_name" AS result_name, "Community_location" AS result_loc, "Community_img_url" AS result_pic, 'community' AS result_type FROM community_list WHERE "Community_name" LIKE CONCAT("@search_text", '%') AND "Type" = 'Created' ORDER BY "Community_name" ASC LIMIT "@row_end" OFFSET "@row_start" LOOP
        RETURN NEXT r;
    END LOOP;
    RETURN;
END
$BODY$
  LANGUAGE plpgsql

然后我将程序称为：

SELECT * FROM search_result('t',3,0)

但没有返回任何值。

Answer 1

你需要：

SELECT * FROM search_result('c');

不仅仅是：

SELECT search_result('c');

如果你想要一个表结果。在SELECT中调用的集返回函数返回复合元组。