Question

我有一个我在日常构建期间运行的Release.proj文件。它应该构建我的云服务，然后将\ bin \ app.publish文件夹的内容复制到另一个新创建的文件夹。它正在构建解决方案，但内容不会被复制。我也尝试过使用DependsOnTaret属性。这似乎是时间问题。 Follweing是我的Release.proj文件的样子：

<?xml version="1.0" encoding="utf-8"?>
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" DefaultTargets="PrepareRelease" ToolsVersion="4.0" >

  <PropertyGroup>
    <ReleaseFolderPath/>
    <ReleaseFolderPath Condition=" '$(OutDir)'=='' ">$(Configuration)\</ReleaseFolderPath>
    ......
........
.......
    <Configuration Condition="'$(Configuration)'=='' ">Release</Configuration>
  </PropertyGroup>


  <ItemGroup>

    <Package Include="..\AzureCloudService\bin\Release\app.publish\*.*"/>

  </ItemGroup>


  <Target Name="PrepareRelease">

    <MSBuild Targets="Publish" Projects="..\AzureService.sln" Properties="Configuration=Release;">
    </MSBuild>

    <MakeDir Directories="$(ReleaseFolderPath)\Package" />
    <Copy SourceFiles="@(Package)" DestinationFolder="$(ReleaseFolderPath)\Package" />

      </Target>

</Project>

Answer 1

我想在“AzureCloudService \ bin \ Release \ app.publish \”中的文件将在MSBuild发布调用期间创建，对吧？如果是这样，只需在目标中移动ItemGroup定义：

<Target Name="PrepareRelease">

 <MSBuild Targets="Publish" Projects="..\AzureService.sln" Properties="Configuration=Release;" />
 <ItemGroup>
  <Package Include="..\AzureCloudService\bin\Release\app.publish\*.*"/>
 </ItemGroup>

 <MakeDir Directories="$(ReleaseFolderPath)\Package" />
 <Copy SourceFiles="@(Package)" DestinationFolder="$(ReleaseFolderPath)\Package" />

</Target>

当ItemGroup元素在目标之外时，它将在调用任何目标之前定义，这意味着如果在构建开始时没有文件存在，它将为空。

app.publish组件在构建后不会被复制

1 个答案: