我是ROR开发的初学者。我有导航,我希望在每个页面上都有搜索框,当我输入一些关键字时,它应该像在表格字段中查询一样。我尝试使用一些在线教程,但无法做到。 我的表名:教程 这是我在导航栏上的搜索表单
<li><%= link_to 'Login', :controller => 'access', :action => 'login' %></li>
<li><%= link_to 'Sign Up', :controller => 'users', :action => 'new' %></li>
<li><%= link_to 'Logout', :controller => 'access', :action => 'logout' %></li>
<div align="right">
<%= form_tag("/search", method: "get") do %>
<%= label_tag(:q, "Search for:") %>
<%= text_field_tag(:q) %>
<%= submit_tag("Search") %>
<% end %>
</div>
这是我的控制器
class SearchController < ApplicationController
def show
@tutorial = Tutorial.find(params[:q])
respond_to do |format|
format.html # show.html.erb
format.json { render json: @tutorial }
end
end
end
这是我的模特
class Search < ActiveRecord::Base
def @tutorial.search(search)
if search
find(:all, :conditions => ['tutorial_name LIKE ?', "%#{search}%"])
else
find(:all)
end
end
end
我不知道该怎么做。请帮忙
答案 0 :(得分:9)
通常情况下,一个坏名字表示思维错误。我相信模型的名称Search
属于此类别。应该叫Tutorial
,不是吗?搜索您对模型所做的事情,而不是模型本身。
如果这个猜测是正确的并且模型现在被称为Tutorial
并且它有一个名为name
的字段是一个字符串,那么你的模型将是
class Tutorial < ActiveRecord::Base
def self.search(pattern)
if pattern.blank? # blank? covers both nil and empty string
all
else
where('name LIKE ?', "%#{pattern}%")
end
end
end
这使得模型&#34; smart&#34;关于如何搜索教程名称:Tutorial.search('foo')
现在将返回名称中包含foo
的所有教程记录。
因此我们可以创建一个使用这个新功能的控制器:
class SearchController < ApplicationController
def show
@tutorials = Tutorial.search(params[:q])
respond_to do |format|
format.html # show.html.erb
format.json { render json: @tutorial }
end
end
end
相应的视图必须显示教程。你的没有。最简单的方法是编写一个只提供一个教程的部分。说它叫_tutorial.html.erb
。
然后在Search
的视图中,您需要添加
<%= render :partial => @tutorials %>
实际显示搜索结果。
<强>加成强>
我将构建一个小例子。
# Make a new rails app called learning_system
rails new learning_system
# Make a new scaffold for a Tutorial model.
rails g scaffold Tutorial name:string description:text
# Now edit app/models/tutorial.rb to add the def above.
# Build tables for the model.
rake db:migrate
rails s # start the web server
# Now hit http://0.0.0.0:3000/tutorials with a browser to create some records.
<cntrl-C> to kill the web server
mkdir app/views/shared
gedit app/views/shared/_search_box.html.erb
# Edit this file to contain just the <%= form_tag you have above.
# Now add a header at the top of any view you like, e.g.
# at the top of app/views/tutorials/index.html.erb as below
# (or you could use the layout to put it on all pages):
<h1>Listing tutorials</h1>
<%= render :partial => 'shared/search_box' %>
# Make a controller and view template for searches
rails g controller search show
# Edit config/routes.rb to the route you want: get "search" => 'search#show'
# Verify routes:
rake routes
search GET /search/:id(.:format) search#show
tutorials GET /tutorials(.:format) tutorials#index
POST /tutorials(.:format) tutorials#create
new_tutorial GET /tutorials/new(.:format) tutorials#new
edit_tutorial GET /tutorials/:id/edit(.:format) tutorials#edit
tutorial GET /tutorials/:id(.:format) tutorials#show
PUT /tutorials/:id(.:format) tutorials#update
DELETE /tutorials/:id(.:format) tutorials#destroy
# Edit app/controllers/search_controller.rb as above.
# Create app/views/tutorial/_tutorial.html.erb with following content:
<tr>
<td><%= tutorial.name %></td>
<td><%= tutorial.description %></td>
</tr>
# Edit app/views/search/show.html.erb to have following content:
<h1>Show Search Results</h1>
<table>
<%= render :partial => @tutorials %>
</table>
现在尝试一下测试。填写搜索条件并按“搜索”按钮。
答案 1 :(得分:0)
在Rails 6
上,您可以在search
中执行controller.rb
的动作:
def search
keyword = params[:q] #you can get this params from the value of the search form input
@posts = Post.where("title LIKE ?", "%#{keyword}%")
end