Question

我是python中的一个完整的新手。如果你可以帮助我会很棒。我的数据格式有点像这样。如果有人可以帮助我，我将不胜感激。

car    trans  +  1,4,6,8
plane  trans  +  3,5,7,9,4,3
train  trans  -  2,4,6,7
bus    trans  -  1,3,4,5,6,7,8

在以逗号分隔的值中，我试图仅提取＆＃34; eventh＆＃34;数字（第2，第4，第6，第8，第10等）根据第三列的+或 - 值排除并定位。

我想放置＆＃34; eventh＆＃34;从逗号分隔的数据中输出数字，如果是＆＃34; +＆＃34;，则数字转到第四列并将该值加1，然后将其放在第5列。如果是＆＃34; - ＆＃34;，则该数字为第五列，减去该值为1，并将其置于第四列。我知道这是一个复杂的解释，但如果有人能给我一个可以从哪里开始的想法，那将会很棒。感谢

car.1    trans  +  4  5
car.2    trans  +  8  9
plane.1  trans  +  5  6
plane.2  trans  +  9  10
plane.3  trans  +  3  4
train.1  trans  -  3  4
train.2  trans  -  6  7
bus.1    trans  -  2  3
bus.2    trans  -  4  5
bus.3    trans  -  6  7

edit2：经过大家的搜索和帮助后，我现在有了类似的东西。这给了我正确的输出，但我现在唯一的问题是我无法正确命名。（即car.1，car.2，car.3，plane.1，plane.2 ....等等）有人可以让我深入了解这个问题吗？

import sys
import string
infileName = sys.argv[1]
outfileName = sys.argv[2]

def getGenes(infile, outfile):

infile = open(infileName,"r")
outfile = open(outfileName, "w")

while 1:
    line = infile.readline()
    if not line: break
    wrds = string.split(line)
    comma = string.split(wrds[3], ",")
    print(comma)
    fivess = comma[1::2]
    print(fivess)

    if len(wrds) >= 2:
        name = wrds[0]
        chr = wrds[1]
        type = wrds[2]
        print(type)
    if type == "+":
        for jj in fivess:
            start = jj
            stop = string.atoi(jj)+1
            outfile.write('%s\t%s\t%s\t%s\t%s\n' %(name, chr, type, start, stop))           
    elif type == "-":
        for jj in fivess:
            stop = jj
            start= string.atoi(jj)-1
            outfile.write('%s\t%s\t%s\t%s\t%s\n' %(name, chr, type, start, stop))   



 getGenes(infileName, outfileName)

Answer 1

按标签拆分每一行;然后在逗号上拆分最后一项（数字列表）。这将为您提供所有用于处理的位。

Answer 2

您可以使用split方法来执行此操作：

txt = """car    trans  +  1,4,6,8
plane  trans  +  3,5,7,9,4,3
train  trans  -  2,4,6,7
bus    trans  -  1,3,4,5,6,7,8"""
lines = txt.split("\n")
for line in lines:
    vehicle,vehicle_type,action,numbers = line.split('\t')
    numbers_list = numbers.split(',')

您只能通过以下方式从列表中获取偶数：

even_locations_list = numbers_list[1::2] #starting from position 1 (the second object) and jumping 2 steps at a time)

Answer 3

拆分的默认实现在任何空格（空格，制表符，你有什么）上拆分。

with open('infile.txt','r') as infile, open('outfile.txt','w') as outfile:
    for line in infile:
        name, group, op, elements = line.split()
        elements = [int(i) for i in elements.split(',')[1::2]]
        for idx, val in enumerate(elements):
            if op == '-':
                col4, col5 = val - 1, val
            else:
                col4, col5 = val, val + 1
            output = "\t".join(map(str,
                        ["{}.{}".format(name, idx+1), group, op, col4, col5]))
            outfile.write(output + "\n")

以逗号分隔，制表符分隔格式组合数据

3 个答案: