我想进行实时用户名检查,我想使用PHP函数。
-->
<?php
require '../../core/init.php';
?>
<!DOCTYPE html>
<html lang="de">
<head>
<meta charset="UTF-8">
<title>KöppCMS - Registrieren</title>
<link rel="stylesheet" href="../../../css/style.css">
<script type="text/javascript" src="../../../js/jquery.js"></script>
<script type="text/javascript" src="../../../js/footer.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$("#username").keyup(function (e) {
//removes spaces from username
$(this).val($(this).val().replace(/\s/g, ''));
var username = $(this).val(); //get the string typed by user
$.post('users.php', {'username':username}, function(data) { //make ajax call to users.php
$("#user-result").html(data); //dump the data received from PHP page
});
});
});
</script>
</head>
的init.php:
<?php
session_start();
require 'database/connect.php';
require 'classes/users.php';
require 'classes/general.php';
$users = new Users($db);
$general = new General();
$errors = array();
?>
那么如何调用check_username
函数并将值发送给它?
希望你理解我的问题,因为我的英语不太好。
我在users.php中试过这个:
<?php
$users = new Users($db);
echo $users->check_username($_POST['username']);
class Users{
private $db;
public function __construct($database) {
$this->db = $database;
}
public function check_username($data) {
return $data+1;
}
function func1($data){
return $data+1;
}
}
获取此错误:
Notice: Undefined variable: db in C:\xampp\htdocs\kcms\system\cms\user\users.php on line 2
答案 0 :(得分:3)
您的PHP脚本应该执行以下操作:
<?php
require('init.php'); // This contains $users = new Users($db);
echo $users->check_username($_POST['username']);
要在Javascript中使用返回值,请参阅