Question

我的图片文件夹中有几张图片，例如：

User12345_gallery0.png
User12345_profilePic.jpg
User12345_gallery1.png
User12345_gallery2.jpg
User54321_gallery0.png

我尝试做的是将用户传递给我的getimages.php并获取该用户的图片。我之前从未这样做过，所以我在语法上挣扎。这就是我到目前为止所拥有的：

if($_REQUEST['user']){
$ext = array('jpeg', 'png', 'jpg');
$dir = 'images/';
$user = $_REQUEST['user'];
$images = array();
foreach ($ext as $ex){
    if (file_exists(strpos($dir.$user."_gallery", "gallery"))) {
        //add file to $images???
    }
}
}

我想检查文件是否包含用户名和＆＃34; gallery＆＃34;的实例。我怎样才能做到这一点？我是在正确的轨道上吗？

Answer 1

使用glob()和stripos()进行此操作..

<?php

if($_REQUEST['user']){

    $user = $_REQUEST['user'];
    $images = array();
     foreach (glob("images/*.{jpg,png,gif}", GLOB_BRACE) as $filename) {
         if(stripos($filename,$user)!==false && stripos($filename,'gallery')!==false)
            $images[]=$filename;
    }
}

Answer 2

为什么不直接查看目录中的图片名称并返回给您的用户？

$ext = array('jpeg', 'png', 'jpg');
$dir = 'images/';
$user = $_REQUEST['user'];

// the length of your username (for the expression bellow)
$usernamelength  = strlen($user); 

// read a list of all files into an array
$filesindirarray = scandir($dir);

// loop through the list
foreach($filesindirarray as $filename)
{
   // does the filename start with
   if(substr($filename,0,($usernamelength+8)) ==  $user .'_gallery')
   {

      // fish out the files extension
      $fileext = pathinfo($filename, PATHINFO_EXTENSION);

      // if the extension of the files is in your list
      if(in_array($fileext,$ext))
         // add to images
    }
}

PHP在服务器上查找包含某些字符串的文件

2 个答案: