Question

我必须从文件中提取具有特定格式的字符串。即字符串格式为1后跟连字符和7位数。

for ex.

    #CARES# AR_NUMBER=1-4742637

这里我只需要提取1-4742637。帮助我，如何提取？

Answer 1

以下内容将捕获：/\b(1-\d{7})\b/

正如所示：

use strict;
use warnings;

my $text = <<'END_TEXT';
for ex.

    #CARES# AR_NUMBER=1-4742637
END_TEXT

if ($text =~ /\b(1-\d{7})\b/) {
    print "$1";
}

输出：

1-4742637

Answer 2

if ($subject =~ m/(1-[\d]+)/) {
    # Successful match
} else {
    # Match attempt failed
}


(1-[\d]+)

Match the regular expression below and capture its match into backreference number 1 «(1-[\d]+)»
   Match the characters “1-” literally «1-»
   Match a single digit 0..9 «[\d]+»
      Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»

Answer 3

你可以这样做：

([0-9-]+)

或特别针对您的情况：

(1-\d{7})

并且第一个捕获的组\1或$1将包含您想要的内容。

演示：http://regex101.com/r/pY4gB6

Answer 4

请尝试

$var =~ /1-\d{7}/

匹配次数

{}

Answer 5

1-\d{7}

将选择所需的部分。

从文件中的一行中提取数字和连字符

5 个答案: