Question

我正在尝试使用Python3.x解析XML文件。如果找到标签，我想返回True，否则返回False。我试图一次读取一行并检查 - 如果找不到则使用递归，但我不确定实现这一目标的最有效方法是什么。实现这一目标的最有效方法是什么？这是我的代码：

class XmlFinder():
    def __init__(self, filename):
        self._filename = filename
        self._tokens = []

    def find(self, tag):
        ''' Accepts tag to search for - Parse the file, return True if tag is found and False if not. '''
        self._tag = tag
        with open(self._filename, 'rt') as f:
            for line in f:
                line = line.strip()
                tokens = line.split()
                if self._tag == self._tokens:
                    return True
                else:
                    return False
             XmlFinder.find(self, self._tag)

def main():
    x = XmlFinder("filename")
    tag = '<to/>'
    x.find(tag)
main()

我以前从未解析过XML文件，所以这对我来说是全新的。

Answer 1

考虑使用像BeautifulSoup

这样的库

from BeautifulSoup import BeautifulStoneSoup

class XmlFinder():
    def __init__(self, filename):
        self._filename = filename
        with file(filename, "r") as file_h:
            self.soup = BeautifulStoneSoup(file_h.read())

    def find(self, tag):
        return True if self.soup.find(tag) else False

def main():
    x = XmlFinder("filename")
    tag = 'to'
    x.find(tag)
main()

使用Python解析XML文件

1 个答案: