Question

我使用ajax获取get请求，查询数据库，然后（至少应该）返回一个json对象。问题是当我尝试创建json对象时。我收到内部服务器错误500.感谢您的帮助。

视图：

def fabric(request, id):

      test = Topics.objects.get(topicId= id)
      ids = Topics.objects.get(topic= test)

      fabrics = [model_to_dict(fabric) for fabric in Fabrics.objects.filter(fabTopic_id=ids.id)]
      print fabrics                     #prints fabrics string 
      fabric_list = json.dumps(fabrics)
      print "test"                      #doesn't print

      return HttpResponse(fabric_list, content_type='application/json')

印花面料字符串：

[{'fabTopic': 1, 'isPremium': False, 'fabWeave': u'', 'fabImage_secondary': <ProcessedImageFieldFile: avatars/cotton2_1.jpg>, 'fabContent': u'', 'fabName': u'Cotton', 'fabImage': <ProcessedImageFieldFile: avatars/cotton1_1.jpg>, 'fabVideoURL': u'', 'fabDye': u'', 'fabFinish': u'', 'fabVideo': u'', 'fabDescription': u'Cotton is a cellulosic fiber obtained from the seed of a cotton plant Depending on the fiber length and/or finish, fabrics can h', u'id': 1}]

Models.py

from django.db import models
from embed_video.fields import EmbedVideoField
from imagekit.models import ProcessedImageField
from imagekit.processors import ResizeToFill

class Catagories(models.Model):
     catagory = models.CharField(max_length=128)
     categoryId = models.CharField(max_length=128)
     def __unicode__(self):
         return self.catagory 

class Topics(models.Model):
    fabCatagory = models.ForeignKey(Catagories)
    topic = models.CharField(max_length=128)
    topicId = models.CharField(max_length=128)
    def __unicode__(self):
         return self.topic 

class Fabrics(models.Model):
    fabTopic = models.ForeignKey(Topics)
    fabName = models.CharField(max_length=128)
    fabContent = models.CharField(max_length=128, blank=True)
    fabWeave = models.CharField(max_length=128, blank=True)
    fabDye = models.CharField(max_length=128, blank=True)
    fabFinish = models.CharField(max_length=128, blank=True)
    fabDescription = models.CharField(max_length=8192) 
    fabImage = ProcessedImageField(upload_to='avatars',
                                       processors=[ResizeToFill(250, 185)],
                                       format='JPEG',
                                       options={'quality': 60},blank=True) 
    fabImage_secondary = ProcessedImageField(upload_to='avatars',
                                       processors=[ResizeToFill(500, 370)],
                                       format='JPEG',
                                       options={'quality': 60},blank=True)
    fabVideo = EmbedVideoField(blank=True)
    fabVideoURL = models.URLField(blank=True)
    isPremium = models.BooleanField(default=False)
    def __unicode__(self):
        return self.fabName

Answer 1

您天真地尝试使用不可序列化的项目序列化dict，例如'fabImage_secondary': <ProcessedImageFieldFile: avatars/cotton2_1.jpg>。

至少，你想使用一个合适的序列化器：

from django.core import serializers
data = serializers.serialize('json', Fabrics.objects.filter(fabTopic_id=ids.id), fields=('a', 'b'))

有关详细信息，请参阅https://docs.djangoproject.com/en/dev/topics/serialization/。

Answer 2

在django之外的python脚本中运行json.dumps并查看错误。

或者只是打开django日志记录以在屏幕上打印错误。

可能json.dumps无法序列化您的Image对象。默认情况下，json.dumps只能序列化和反序列化简单类型，如列表，字符串，数字和字符串。您必须以序列化程序的某些simpler形式提供图像，作为文件（字符串）或字节数组的路径（在python2中也是字符串）。

json.dumps上的Django内部服务器错误

2 个答案: