Question

我有一个图像并用MS Paint和GDI旋转它。我想表明两种方法的旋转图像是相同的。

这是我用GDI旋转图像的代码

#include <GDIPlus.au3>

_GDIPlus_Startup()

$hImage1 = _GDIPlus_ImageLoadFromFile(@ScriptDir & "\Picture.gif")
$hGraphic1 = _GDIPlus_ImageGetGraphicsContext($hImage1)
$hImage2 = _GDIPlus_BitmapCreateFromGraphics(_GDIPlus_ImageGetWidth($hImage1), _GDIPlus_ImageGetHeight($hImage1), $hGraphic1)
$hGraphic2 = _GDIPlus_ImageGetGraphicsContext($hImage2)

$matrix = _GDIPlus_MatrixCreate()
_GDIPlus_MatrixRotate($matrix,90)
_GDIPlus_GraphicsSetTransform($hGraphic2, $matrix)
_GDIPlus_GraphicsDrawImage($hGraphic2, $hImage1, 0, -590)

_GDIPlus_ImageSaveToFile($hImage2, @ScriptDir & "\out.gif")

_GDIPlus_MatrixDispose($matrix)
_GDIPlus_GraphicsDispose($hGraphic1)
_GDIPlus_GraphicsDispose($hGraphic2)
_GDIPlus_ImageDispose($hImage1)
_GDIPlus_ImageDispose($hImage2)

 _GDIPlus_ShutDown ()

然后我用这段代码比较了2张图片：

$bm1 = _GDIPlus_ImageLoadFromFile(@ScriptDir & "\Picture1.gif")
$bm2 = _GDIPlus_ImageLoadFromFile(@ScriptDir & "\out.gif")

if ComparePicture($bm1, $bm2) == True Then
   MsgBox(0, "Test result", "Same image!")
Else
   MsgBox(0, "Test result", "Different image!")
EndIf

_GDIPlus_ImageDispose($bm1)
_GDIPlus_ImageDispose($bm2)
_GDIPlus_Shutdown()

Func ComparePicture($bm1, $bm2)

$Bm1W = _GDIPlus_ImageGetWidth($bm1)
$Bm1H = _GDIPlus_ImageGetHeight($bm1)
$BitmapData1 = _GDIPlus_BitmapLockBits($bm1, 0, 0, $Bm1W, $Bm1H, $GDIP_ILMREAD, $GDIP_PXF08INDEXED )
$Stride = DllStructGetData($BitmapData1, "Stride")
$Scan0 = DllStructGetData($BitmapData1, "Scan0")

$ptr1 = $Scan0
$size1 = ($Bm1H - 1) * $Stride + ($Bm1W - 1) * 4


$Bm2W = _GDIPlus_ImageGetWidth($bm2)
$Bm2H = _GDIPlus_ImageGetHeight($bm2)
$BitmapData2 = _GDIPlus_BitmapLockBits($bm2, 0, 0, $Bm2W, $Bm2H, $GDIP_ILMREAD, $GDIP_PXF08INDEXED)
$Stride = DllStructGetData($BitmapData2, "Stride")
$Scan0 = DllStructGetData($BitmapData2, "Scan0")

$ptr2 = $Scan0
$size2 = ($Bm2H - 1) * $Stride + ($Bm2W - 1) * 4

$smallest = $size1
If $size2 < $smallest Then $smallest = $size2
$call = DllCall("msvcrt.dll", "int:cdecl", "memcmp", "ptr", $ptr1, "ptr", $ptr2, "int", $smallest)



_GDIPlus_BitmapUnlockBits($bm1, $BitmapData1)
_GDIPlus_BitmapUnlockBits($bm2, $BitmapData2)

Return ($call[0]=0)
EndFunc

我尝试更改文件类型，颜色深度等，但我无法获取代码以显示它们是相同的。当我不旋转图片时，

_GDIPlus_MatrixRotate($matrix,0)

然后它识别出相同的图像。当我向右旋转90时，它没有。有谁知道可能会发生什么？

由于

作为参考，AutoIt论坛here也提出了这个问题。

Answer 1

我认为$GDIP_PXF08INDEXED正在以不同方式修改图像。尝试不设置它，它应该工作。

此外，您可以使用此代码翻转图片：

$hImage1 = _GDIPlus_ImageLoadFromFile(@ScriptDir & "\Picture1.gif")
_GDIPlus_ImageRotateFlip($hImage1, 1) ;90°

_GDIPlus_ImageSaveToFile($hImage1, @ScriptDir & "\out.gif")

_GDIPlus_ImageDispose($hImage1)

BR，

UEZ

AutoIT脚本 - 将Paint的旋转图像与GDI的旋转图像进行比较

1 个答案: