我试图在微调器上从基于数据库的选定项检索数据。 这是我的数据库结构
这是我的活动:
public class help_activity extends Activity implements OnClickListener{
Spinner spinner1;
SQLiteConnector sqlConnect;
ListView lvUsers;
Button b1;
String colors[] = {"Bristleback","Sven","Tiny","Undying", "Naix","Weaver","Spectre","Lich"};
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.layout_help);
spinner1 = (Spinner) findViewById(R.id.spinner1);
lvUsers = (ListView) findViewById(R.id.listView1);
b1 = (Button) findViewById(R.id.btn1);
sqlConnect = new SQLiteConnector(this);
addListenerOnSpinnerItemSelection();
final String nameSelected = spinner1.getSelectedItem().toString();
final ArrayAdapter<String> adapter = new ArrayAdapter<String>(
this, android.R.layout.simple_list_item_1, sqlConnect.getAllRecord(nameSelected));
b1.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
if (nameSelected.equals("Bristleback")) {
lvUsers.setAdapter(adapter);
adapter.notifyDataSetChanged();
}
else if (nameSelected.equals("Sven")) {
lvUsers.setAdapter(adapter);
adapter.notifyDataSetChanged();
}
else if (nameSelected.equals("Tiny")) {
lvUsers.setAdapter(adapter);
}
else if (nameSelected.equals("Undying")) {
lvUsers.setAdapter(adapter);
adapter.notifyDataSetChanged();
}
else if (nameSelected.equals("Naix")) {
lvUsers.setAdapter(adapter);
adapter.notifyDataSetChanged();
}
else if (nameSelected.equals("Weaver")) {
lvUsers.setAdapter(adapter);
adapter.notifyDataSetChanged();
}
else if (nameSelected.equals("Spectre")) {
lvUsers.setAdapter(adapter);
adapter.notifyDataSetChanged();
}
else if (nameSelected.equals("Lich")) {
lvUsers.setAdapter(adapter);
adapter.notifyDataSetChanged();
}
// TODO Auto-generated method stub
}
});
}
public void addListenerOnSpinnerItemSelection() {
ArrayAdapter<String> spinnerArrayAdapter = new ArrayAdapter<String>
(this, android.R.layout.simple_spinner_dropdown_item,colors );
spinner1.setAdapter(spinnerArrayAdapter);
}
@Override
public void onClick(View v) {
}
}
这是我从数据库中检索数据的方法:
public List<String> getAllRecord(String nameSelected) {
List<String> namagambar = new ArrayList<String>();
String selectQuery = "SELECT * FROM " + TABLE_RECORD + " WHERE "
+ HERO_NAME + "=?";
database = dbHelper.getReadableDatabase();
cursor = database.rawQuery(selectQuery, new String[]{nameSelected});
if (cursor.moveToFirst()) {
do {
namagambar.add(cursor.getString(1));
} while (cursor.moveToNext());
}
database.close();
return namagambar;
}
因此,当用户在微调器上选择一个项目时,nama_hero上的数据将根据微调器上选定的名称英雄显示在列表视图中。但是当我运行我的代码时,它只显示了数据库中的数据顶部 因此,当我在微调器上选择名称Sven时,listview上显示的名称不是“sven”而是“bristleback”。当我选择其他英雄名字时也会发生这种情况。
我认为我在旋转器中获取所选项目名称的方法不起作用
请帮我解决这个问题。
已解决!!!
答案 0 :(得分:1)
完成!!
我已经解决了这个问题,感谢stackoverflow
我将setOnclickListener更改为此b1.setOnClickListener(this);
移动之前的所有项目:
public void onClick(View v) {
}
答案 1 :(得分:0)
尝试在 ClickListener
b1.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
String nameSelected = spinner1.getSelectedItem().toString();