轨道复杂的形式和与构建的订购

Question

我的复杂形式类似于最近的Ryan Bates screencast

然而，嵌套元素工作正常。我正在创建或更新数据网格，例如通过当天价格为输入的表格。当他们留下一个空白时我的问题就开始了我有nested_attributes_for选项不保存nils并且它可以工作，如果它们只在特定行中保存一个值，它会保存正确的一天，但是当重新加载时，它会将它放在错误的列中。我不知道如何将值连续排序到表单。 IE星期三保存的值将出现在星期一列（正确的行）中。如果他们保存一行的所有值（然后它完美地工作），就不会发生这种情况。

数据存储在DB中，如此

ID OBJECT_ID DAYOFWEEK PRICE并显示如下

+------+----------------+-------+-------+-------+------+-------+
| id   | name           | Mon   | Tue   | Wed   | Thu  | Fri   | -> +2 more days etc
+------+----------------+-------+-------+-------+------+-------+
| 1234 | Some name      | 87.20 | 87.20 | 87.20 | 82.55| 85.48 |
+------+----------------+-------+-------+-------+------+-------+
| 1234 | Some name      | 87.20 | 87.20 | 87.20 | 82.55| 85.48 |
+------+----------------+-------+-------+-------+------+-------+
| 1234 | Some name      | 87.20 | 87.20 | 87.20 | 82.55| 85.48 |
+------+----------------+-------+-------+-------+------+-------+

构建或显示这些值的控制器代码如下：

控制器

@rooms.each do |r|
  ((r.room_rates.size+1)..7).each {
      r.room_rates.build
  }
end

rooms.html.erb

<% @dow = 0 %>
  <tr class="room">
 <td><%= f.text_field :name %></td>

 <% f.fields_for :room_rates do |rates| %>
  <%= render 'rates', :f => rates %>

  <% @dow += 1 %>
 <% end %>

 <td class="delete_mode" style="display:none;">
  <%= f.hidden_field :_destroy %>
  <%= link_to_function "remove", "remove_room(this)" %>
 </td>
  </tr>

rates.html.erb

<td> 
 <%= f.text_field :price, :size => 3 %>
 <%= f.hidden_field :dayofweek, :value => @dow %> 
 <%= f.hidden_field :source, :value => 0 %>
</td>

room_rates模型（来自表单的数据）

+-------+---------+-----------+-------+--------+---------------------------+---------------------------+
| id    | room_id | dayofweek | price | source | created_at                | updated_at                |
+-------+---------+-----------+-------+--------+---------------------------+---------------------------+
| 92745 | 8       | 0         | 1.0   | 0      | 2010-02-23 14:33:05 +0100 | 2010-02-23 14:33:05 +0100 |
| 92746 | 8       | 1         | 2.0   | 0      | 2010-02-23 14:33:05 +0100 | 2010-02-23 14:33:05 +0100 |
| 92747 | 8       | 2         | 3.0   | 0      | 2010-02-23 14:33:05 +0100 | 2010-02-23 14:33:05 +0100 |
| 92748 | 8       | 3         | 4.0   | 0      | 2010-02-23 14:33:05 +0100 | 2010-02-23 14:33:05 +0100 |
| 92749 | 8       | 4         | 5.0   | 0      | 2010-02-23 14:33:05 +0100 | 2010-02-23 14:33:05 +0100 |
| 92750 | 8       | 5         | 6.0   | 0      | 2010-02-23 14:33:05 +0100 | 2010-02-23 14:33:05 +0100 |
| 92751 | 8       | 6         | 7.0   | 0      | 2010-02-23 14:33:05 +0100 | 2010-02-23 14:33:05 +0100 |
| 92752 | 9       | 3         | 5.0   | 0      | 2010-02-23 14:33:33 +0100 | 2010-02-23 14:33:33 +0100 |
+-------+---------+-----------+-------+--------+---------------------------+---------------------------+

在控制台中排序

+---------+-----------+-------+--------+---------------------------+---------------------------+
| room_id | dayofweek | price | source | created_at                | updated_at                |
+---------+-----------+-------+--------+---------------------------+---------------------------+
| 2517    | 0         |       |        |                           |                           |
| 2517    | 1         |       |        |                           |                           |
| 2517    | 2         | 3.0   | 0      | 2010-02-23 17:54:28 +0100 | 2010-02-23 17:54:28 +0100 |
| 2517    | 3         | 4.0   | 0      | 2010-02-23 17:54:28 +0100 | 2010-02-23 17:54:28 +0100 |
| 2517    | 4         |       |        |                           |                           |
| 2517    | 5         |       |        |                           |                           |
| 2517    | 6         |       |        |                           |                           |
+---------+-----------+-------+--------+---------------------------+---------------------------+

Answer 1

错误是在您创建表单时 - 因为您依赖于room_rates的顺序是正确的，您需要将空（已建立）费率放入正确的位置。如果每个房间都有很多房价，您需要生成表格，以便房价在一周中的正确日期。此代码将在新数组中构建，并正确设置新数组：

@rooms.each do |r|
  new_rates = []
  (0..6).each { |dow|
    rate = r.room_rates.find_by_dayofweek(dow)
    if rate
      new_rates << rate
    else 
      new_rates << r.room_rates.build(:dayofweek => dow)
    end
  }
  r.room_rates = new_rates
end

或者，如果您为关联指定订单，则可能只能构建缺失的周数：

// In room model 
has_many :rates, :order => "dayofweek"

// In controller
@rooms.each do |r|
  (0..6).each { |dow|
    if not r.room_rates.find_by_dayofweek(dow)
      r.room_rates.build(:dayofweek => dow)
    end
  }
end