Question

嘿大家，我希望你能帮忙，谢谢你花时间看看

我尝试使用简单的适配器和散列映射在一个活动中使用multilpe listviews

这是我的一些代码......

final ArrayList<HashMap<String,String>> listGeneral = new ArrayList<HashMap<String,String>>();

然后在onCreate之前

在onCreate

setContentView(R.layout.custom_list_view);

        SimpleAdapter adapter1 = new SimpleAdapter(
                this,
                listGeneral,
                R.layout.custom_row_view,
                new String[] {"catGeneral","score1"},
                new int[] {R.id.text1,R.id.text2}
        );

setList1();
 setListAdapter(adapter1);

setList1

public void setList1(){

        HashMap<String,String> temp = new HashMap<String,String>();
        temp.put("catGeneral","General Knowledge Lv1");
        temp.put("score1", level3);
        listGeneral.add(temp);

        HashMap<String,String> temp1 = new HashMap<String,String>();
        temp1.put("catGeneral","General Knowledge Lv2");
        temp1.put("score1", level4);
        listGeneral.add(temp1);

        HashMap<String,String> temp2 = new HashMap<String,String>();
        temp2.put("catGeneral","General Knowledge Lv3");
        temp2.put("score1", level2);
        listGeneral.add(temp2);
}

和itemListener

protected void onListItemClick(ListView l, View v, int position, long id) {
        super.onListItemClick(l, v, position, id);


        if (position == 0){
        Toast.makeText(this, "one", Toast.LENGTH_LONG).show();
        }
        else if (position == 1){
            Toast.makeText(this, "two", Toast.LENGTH_LONG).show();
            }
        else if (position == 2){
            Toast.makeText(this, "three", Toast.LENGTH_LONG).show();
            }
        else if (position == 3){
            Toast.makeText(this, "four", Toast.LENGTH_LONG).show();
            }
        else if (position == 4){
            Toast.makeText(this, "five", Toast.LENGTH_LONG).show();
            }
       }

和xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >


    <ListView android:id="@id/android:list"
        android:layout_width="fill_parent"
        android:layout_height="fill_parent"
        android:background="#000fff"
        android:layout_weight="2"
        android:drawSelectorOnTop="false">
    </ListView>

    <TextView android:id="@id/android:empty"
        android:layout_width="fill_parent" 
        android:layout_height="fill_parent" 
        android:background="#FFff00"
        android:text="No data"
    />

</LinearLayout>

所有这些都适用于一个列表视图。但是当我添加第二个列表时

final ArrayList<HashMap<String,String>> listPopCulture = new ArrayList<HashMap<String,String>>();
SimpleAdapter adapter2 = new SimpleAdapter(
                this,
                listPopCulture,
                R.layout.custom_row_view,
                new String[] {"catPopCulture","score2"},
                new int[] {R.id.text1,R.id.text2}
        );


setList2();
setListAdapter(adapter2);

public void setList2(){

        HashMap<String,String> temp = new HashMap<String,String>();
        temp.put("catPopCulture","The 60's");
        temp.put("score2", level3);
        listPopCulture.add(temp);

        HashMap<String,String> temp1 = new HashMap<String,String>();
        temp1.put("catPopCulture","The 70's");
        temp1.put("score2", level4);
        listPopCulture.add(temp1);

        HashMap<String,String> temp2 = new HashMap<String,String>();
        temp2.put("catPopCulture","The 80's");
        temp2.put("score2", level2);
        listPopCulture.add(temp2);
}

我不知道如何为第二个列表执行第二个itemListener，以及如何调用第二个列表，因为我认为第一个列表是由android:id="@id/android:list"调用的我尝试过的一切都没有用......

是因为简单的适配器因为它的id而无法在每个活动的多个列表上设置？以及如何在一个xml文件中声明第二个或更多listviews。最后我想要一个带有scrollview的布局，其中包含textview然后是listview，然后是另一个textview和另一个listview ....任何帮助都会很棒

这里编辑的答案几乎都是他们的。但我需要onItemListener for list2和list3

setContentView(R.layout.custom_list_view);

        ListView list2 = (ListView)findViewById(R.id.list2);
        ListView list3 = (ListView)findViewById(R.id.list3);



        SimpleAdapter adapter1 = new SimpleAdapter(
                this,
                listGeneral,
                R.layout.custom_row_view,
                new String[] {"catGeneral","score1"},
                new int[] {R.id.text1,R.id.text2}
        );
        //list1.setAdapter(adapter1);


        SimpleAdapter adapter2 = new SimpleAdapter(
                this,
                listPopCulture,
                R.layout.custom_row_view,
                new String[] {"catPopCulture","score2"},
                new int[] {R.id.text1,R.id.text2}
        );

        SimpleAdapter adapter3 = new SimpleAdapter(
                this,
                listKids,
                R.layout.custom_row_view,
                new String[] {"catKids","score3"},
                new int[] {R.id.text1,R.id.text2}
        );

        setList1();
        setList2();
        setList3();

                setListAdapter(adapter1);
        list2.setAdapter(adapter2);
        list3.setAdapter(adapter3);

        //end oncreate  
    }

    public void setList1(){

        HashMap<String,String> temp = new HashMap<String,String>();
        temp.put("catGeneral","General Knowledge Lv1");
        temp.put("score1", level3);
        listGeneral.add(temp);

        HashMap<String,String> temp1 = new HashMap<String,String>();
        temp1.put("catGeneral","General Knowledge Lv2");
        temp1.put("score1", level4);
        listGeneral.add(temp1);

        HashMap<String,String> temp2 = new HashMap<String,String>();
        temp2.put("catGeneral","General Knowledge Lv3");
        temp2.put("score1", level2);
        listGeneral.add(temp2);

        HashMap<String,String> temp3 = new HashMap<String,String>();
        temp3.put("catGeneral","General Knowledge Lv4");
        temp3.put("score1", level3);
        listGeneral.add(temp3);

        HashMap<String,String> temp4 = new HashMap<String,String>();
        temp4.put("catGeneral", "General Knowledge Lv5");
        temp4.put("score1", level1);
        listGeneral.add(temp4);

        HashMap<String,String> temp5 = new HashMap<String,String>();
        temp5.put("catGeneral", "General Knowledge Lv6");
        temp5.put("score1", level1);
        listGeneral.add(temp5);
    }

我的工作听众列表1

 //list 1 listener
        protected void onListItemClick(ListView l, View v, int position, long id) {
            super.onListItemClick(l, v, position, id);
            if (position == 0){
            Toast.makeText(this, "one", Toast.LENGTH_LONG).show();
            }
            else if (position == 1){
                Toast.makeText(this, "two", Toast.LENGTH_LONG).show();
                }
            else if (position == 2){
                Toast.makeText(this, "three", Toast.LENGTH_LONG).show();
                }
            else if (position == 3){
                Toast.makeText(this, "four", Toast.LENGTH_LONG).show();
                }
            else if (position == 4){
                Toast.makeText(this, "five", Toast.LENGTH_LONG).show();
                }
           }

我已尝试过list2 onItemClick

list2.setOnItemClickListener(new OnItemClickListener() {

            @Override
            public void onItemClick(AdapterView<?> arg0, View v, int position, long id) {
                if (position == 0){
                    Toast.makeText(this, "one", Toast.LENGTH_LONG).show();
                    }
                    else if (position == 1){
                        Toast.makeText(this, "two", Toast.LENGTH_LONG).show();
                        }
                    else if (position == 2){
                        Toast.makeText(this, "three", Toast.LENGTH_LONG).show();
                        }
                    else if (position == 3){
                        Toast.makeText(this, "four", Toast.LENGTH_LONG).show();
                        }
                    else if (position == 4){
                        Toast.makeText(this, "five", Toast.LENGTH_LONG).show();
                        }
            }
        });

关于list2和list3 onItemClick的任何想法？

Answer 1

在xml中放两个列表： -

<?xml version="1.0" encoding="utf-8"?>

<ListView android:id="@+id/list1"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:background="#000fff"
    android:layout_weight="2"
    android:drawSelectorOnTop="false">
</ListView>

<ListView android:id="@+id/list2"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:background="#000fff"
    android:layout_weight="2"
    android:drawSelectorOnTop="false">
</ListView>

<TextView android:id="@id/android:empty"
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent" 
    android:background="#FFff00"
    android:text="No data"
/>

现在在您的主要活动中，像上面一样创建适配器。获取这样的列表引用： -

ListView list1 = (ListView)findViewById(R.id.list1);
ListView list2 = (ListView)findViewById(R.id.list2);
list1.setAdapter(adapter);
list2.setAdapter(secondadapter);

使用多个listviews与简单的适配器和hashmap

1 个答案: