Question

尝试使用以前的线程自己解决这个问题，但其他人的例子并没有帮助我弄清楚我需要什么。独立文件本身可以工作，数据很好地插入到数据库中......但我正在尝试将这些文档调整为一体化的单个PHP文档。

我想我会抛弃我正在尝试做的事情和我到目前为止的代码，也许有人会理解我想要完成的事情，并能够解释如何去做。

我基本上有一个带有form（form.php）的PHP文档，它使用POST将表单数据发送到第二个PHP文档，然后将表单数据发送到MySQL数据库。我希望用户能够使用相同的文档发布数据并重置数据字段，以便用户和提交通过表单输入更多信息。我希望让用户知道由于字段不完整而导致的错误，我希望用户能够知道成功的条目（我将使用echo函数）。

form.php如下：

<html>
<head>
    <link rel="stylesheet" type="text/css" href="form.css">
    <title>MySQL Database Creation System</title>
    <script src="jquery-1.11.0.min.js"></script>
</head>
<body>
    <div class="wrapper">
        <img src="eris.png" align="middle">
        <form action="insert.php" method="post">
        Firstname: <input type="text" size="16" name="firstname">
        Lastname: <input type="text" size="16" name="lastname">
        Age: <input type="text" size="1" maxlength="3" name="age">
        <input type="submit" class="button">
        </form>
    </div>
</body>

insert.php如下：

<html>
<head>
    <link rel="stylesheet" type="text/css" href="insert.css">
    <title>MySQL Database Creation System</title>
</head>
<body>
    <div class="wrapper">
    <img src='eris.png' align='middle'>
        <?php
        if ( (trim($_POST['firstname']) == "") || (trim($_POST['lastname']) == "") || (trim($_POST['age']) == "") )
        {
            echo "<p>ERROR: All fields must be completed</p>";
            echo "<p><a href='form.php'>Return to Form</a></p>";
        }
        else
        {
            $con=mysqli_connect("localhost","test","test","my_db");
            // Check connection
            if (mysqli_connect_errno())
            {
              echo "<br>Failed to connect to MySQL: " . mysqli_connect_error();
            }

            // escape variables for security
            $firstname = mysqli_real_escape_string($_POST['firstname']);
            $lastname = mysqli_real_escape_string($_POST['lastname']);
            $age = mysqli_real_escape_string($_POST['age']);

            $sql="INSERT INTO Persons (FirstName, LastName, Age) 
            VALUES ('$firstname', '$lastname', '$age')";

            if (!mysqli_query($con,$sql))
            {
              die('<br>Error: ' . mysqli_error($con));
            }

            mysqli_close($con);

            echo "<p>New item added.</p>";
            echo "<p><a href='form.php'>Return to Form</a></p>";
        }
        ?>
    </div>

</body>

提前感谢您提供的任何帮助。

Answer 1

恢复您的form.php，如下所示 -

我在这做了什么 -

1）<form action="insert.php" method="post">
要
<form action="" method="post">

2）在php code
中添加了所有form.php
<?php if ( (trim($_POST['firstname']) == "") || (trim($_POST['lastname']) == "") || (trim($_POST['age']) == "") ) { echo "<p>ERROR: All fields must be completed</p>"; echo "<p><a href='form.php'>Return to Form</a></p>"; } else { $con=mysqli_connect("localhost","test","test","my_db"); // Check connection if (mysqli_connect_errno()) { echo "<br>Failed to connect to MySQL: " . mysqli_connect_error(); } // escape variables for security $firstname = mysqli_real_escape_string($_POST['firstname']); $lastname = mysqli_real_escape_string($_POST['lastname']); $age = mysqli_real_escape_string($_POST['age']); $sql="INSERT INTO Persons (FirstName, LastName, Age) VALUES ('$firstname', '$lastname', '$age')"; if (!mysqli_query($con,$sql)) { die('<br>Error: ' . mysqli_error($con)); } mysqli_close($con); echo "<p>New item added.</p>"; echo "<p><a href='form.php'>Return to Form</a></p>"; } ?> <html> <head> <link rel="stylesheet" type="text/css" href="form.css"> <title>MySQL Database Creation System</title> <script src="jquery-1.11.0.min.js"></script> </head> <body> <div class="wrapper"> <img src="eris.png" align="middle"> <form action="" method="post"> Firstname: <input type="text" size="16" name="firstname"> Lastname: <input type="text" size="16" name="lastname"> Age: <input type="text" size="1" maxlength="3" name="age"> <input type="submit" class="button"> </form> </div> </body>

Answer 2

我希望我明白这一点。在这种情况下，你就在附近。只需像这样合并你的脚本：

<?php
// check if there is a post request ...
// if not - nothing happens
if(!empty($_POST))
{
   if ( (trim($_POST['firstname']) == "") || (trim($_POST['lastname']) == "") || (trim($_POST['age']) == "") )
    {
        echo "<p>ERROR: All fields must be completed</p>";
        echo "<p><a href='form.php'>Return to Form</a></p>";
    }
    else
    {
        // your inser code
        $con=mysqli_connect("localhost","test","test","my_db");
        // Check connection
        if (mysqli_connect_errno())
        {
          echo "<br>Failed to connect to MySQL: " . mysqli_connect_error();
        }

        // escape variables for security
        $firstname = mysqli_real_escape_string($_POST['firstname']);
        $lastname = mysqli_real_escape_string($_POST['lastname']);
        $age = mysqli_real_escape_string($_POST['age']);

        $sql="INSERT INTO Persons (FirstName, LastName, Age) 
        VALUES ('$firstname', '$lastname', '$age')";

        if (!mysqli_query($con,$sql))
        {
          die('<br>Error: ' . mysqli_error($con));
        }

        mysqli_close($con);

        echo "<p>New item added.</p>";
        echo "<p><a href='form.php'>Return to Form</a></p>";
    }
}
?>

<html>
<head>
    <link rel="stylesheet" type="text/css" href="form.css">
    <title>MySQL Database Creation System</title>
    <script src="jquery-1.11.0.min.js"></script>
</head>
<body>
    <div class="wrapper">
        <img src="eris.png" align="middle">
        <!-- change insert.php to form.php -->
        <form action="form.php" method="post">
            Firstname: <input type="text" size="16" name="firstname">
            Lastname: <input type="text" size="16" name="lastname">
            Age: <input type="text" size="1" maxlength="3" name="age">
        <input type="submit" class="button">
    </form>
</div>

我希望这接近你的期望。

Answer 3

然后您的表单页面应该是这样的。

    <html>
    <head>
        <link rel="stylesheet" type="text/css" href="form.css">
        <title>MySQL Database Creation System</title>
        <script src="jquery-1.11.0.min.js"></script>
    </head>
    <body>
        <div class="wrapper">
            <img src="eris.png" align="middle">
            <form action="" method="post">
            Firstname: <input type="text" size="16" name="firstname">
            Lastname: <input type="text" size="16" name="lastname">
            Age: <input type="text" size="1" maxlength="3" name="age">
            <input type="submit" class="button">
            </form>
        </div>
    </body>
    <?php
    if ( (trim($_POST['firstname']) == "") || (trim($_POST['lastname']) == "") || (trim($_POST['age']) == "") )
    {
        echo "<p>ERROR: All fields must be completed</p>";
        echo "<p><a href='form.php'>Return to Form</a></p>";
    }
    else
    {
        $con=mysqli_connect("localhost","test","test","my_db");
        // Check connection
        if (mysqli_connect_errno())
        {
          echo "<br>Failed to connect to MySQL: " . mysqli_connect_error();
        }

        // escape variables for security
        $firstname = mysqli_real_escape_string($_POST['firstname']);
        $lastname = mysqli_real_escape_string($_POST['lastname']);
        $age = mysqli_real_escape_string($_POST['age']);

        $sql="INSERT INTO Persons (FirstName, LastName, Age) 
        VALUES ('$firstname', '$lastname', '$age')";

        if (!mysqli_query($con,$sql))
        {
          die('<br>Error: ' . mysqli_error($con));
        }

        mysqli_close($con);

        echo "<p>New item added.</p>";
        echo "<p><a href='form.php'>Return to Form</a></p>";
    }
    ?>

感谢名单

使用PHP POST方法发布到同一页面

3 个答案: