Question

我查看了几个社区论坛，我无法弄清楚如何在验证失败后保留选择选项值。

以下是适用于我的代码，但提交提交按钮后，值会消失。

<select id="service" name="service" class="searchoption">
             <option value="">-- Select Service Name --</option>
             <?php
             $resultservice = mysqli_query($con,"Select * from services") ?>
             <?php
             while ($line = mysqli_fetch_array($resultservice)) {
             ?>
             <option value="<?php echo $line['serviceid'];?>"> <?php echo $line['service'];?> </option>

            <?php
            }
            ?>
            </select>

以下是我尝试过但对我不起作用的内容：

<select id="service" name="service" class="searchoption">
             <option value="">-- Select Service Name --</option>
             <?php
             $resultservice = mysqli_query($con,"Select * from services") ?>
             <?php
             while ($line = mysqli_fetch_array($resultservice)) {
             ?>
             <option value="<?php echo $line['serviceid']; if ($_POST['service'] == $service) {echo 'selected="selected"'} echo $line['serviceid']; ?>"> <?php echo $line['service'];?> </option>

            <?php
            }
            ?>
            </select>

Answer 1

<form action="" method="POST">
<select name="list" id="list">
    <option value="item1">item1</option>
    <option value="item2">item2</option>
    <option value="item3">item3</option>
</select>
<input type="submit" />
</form>

<script type="text/javascript">
     document.getElementById('list').value = "<?php echo $_POST['list']?>";
</script>

Answer 2

可能是一个小错误，但发现无效＆gt;在以下代码中

 <option value="<?php echo $line['serviceid']; if ($_POST['service'] == $service) {echo 'selected="selected"'} echo $line['serviceid']; ?>"> <?php echo $line['service'];?> </option>

试试这个

 <option value="<?php echo $line['serviceid']; if ($_POST['service'] == $service) {echo     'selected="selected"'}?> echo $line['serviceid']; <?php echo $line['service'];?>" </option>

希望这会有所帮助

如何在php中提交表单后保留选择选项

2 个答案: