我是一个关于在线出版系统的项目,在这个网站上有用户。我已经在我的网站上获得了MySql结果,由于某种原因,结果是随机的。我想使用select,option标签对下拉列表列表对用户数据库结果进行排序...我应该使用什么才能使此功能正常工作? 这是我想要排序的代码:
<form>
<label>Sort By:</label>
<select name="sort" id="sort" style="float: left;">
<option value="ID">Id Number</option>
<option value="name">Name A-Z</option>
<option value="surname">Name Z-A</option>
<option value="title">Academic Title</option>
<option value="department">Departments</option>
</select>
</form>
答案 0 :(得分:1)
试试这个
<html>
<head>
<script>
function sortResult(str)
{
if (str=="")
{
document.getElementById("result").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("result").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","results.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>
<form>
<select name="sortby" onchange="sortResult(this.value)">
<option value="ID">Id Number</option>
<option value="name">Name A-Z</option>
<option value="surname">Name Z-A</option>
<option value="title">Academic Title</option>
<option value="department">Departments</option>
</select>
</form>
<br>
<div id="result"><b>Results will be listed here.</b></div>
</body>
</html>
你的results.php
<?php
$q = $_GET['q'];
$con = mysqli_connect('localhost','username','password','my_db');
if (!$con)
{
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"database");
$sql="SELECT * FROM tablename ORDER BY ".$q;
$result = mysqli_query($con,$sql);
echo "<table border='1'>
<tr>
<th>ID</th>
<th>Name</th>
<th>Surname</th>
<th>Title</th>
<th>Department</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" .$row['ID']. "</td>";
echo "<td>" .$row['name']. "</td>";
echo "<td>" .$row['surname'] ."</td>";
echo "<td>" .$row['title']. "</td>";
echo "<td>" .$row['department']. "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>