Question

我使用以下代码在iOS 7.1中获取联系人

 CFErrorRef *error=nil;
    ABAddressBookRef addressbook=ABAddressBookCreateWithOptions(NULL, error);
    CFArrayRef allpeople=ABAddressBookCopyArrayOfAllPeople(addressbook);
    CFIndex npeople=ABAddressBookGetPersonCount( addressbook );


    ABAddressBookRef addressBookRef = ABAddressBookCreateWithOptions(NULL, NULL);

    if (ABAddressBookGetAuthorizationStatus() == kABAuthorizationStatusNotDetermined) {
        ABAddressBookRequestAccessWithCompletion(addressBookRef, ^(bool granted, CFErrorRef error) {
            if (granted) {


                 NSLog(@"access granteddsddsdd");
                for ( int i = 0; i < npeople; i++ )
                {
                    NSLog(@"access granted");
                    ABRecordRef ref = CFArrayGetValueAtIndex( allpeople, i );
                    NSString *firstName = (__bridge NSString *)(ABRecordCopyValue(ref, kABPersonFirstNameProperty));
                    NSString *lastName = (__bridge NSString *)(ABRecordCopyValue(ref, kABPersonLastNameProperty));
                    NSLog(@"Name:%@ %@", firstName, lastName);    }


                // First time access has been granted, add the contact
            } else {
                // User denied access
                // Display an alert telling user the contact could not be added
            }
        });
    }
    else if (ABAddressBookGetAuthorizationStatus() == kABAuthorizationStatusAuthorized) {
        NSLog(@"access granted1");

        for ( int i = 0; i < npeople; i++ )
        {
            ABRecordRef ref = CFArrayGetValueAtIndex( allpeople, i );
            NSString *firstName = (__bridge NSString *)(ABRecordCopyValue(ref, kABPersonFirstNameProperty));
            NSString *lastName = (__bridge NSString *)(ABRecordCopyValue(ref, kABPersonLastNameProperty));
            NSLog(@"Name:%@ %@", firstName, lastName);    }


        // The user has previously given access, add the contact
    }
    else {

        NSLog(@"access granted2");
        for ( int i = 0; i < npeople; i++ )
        {
            ABRecordRef ref = CFArrayGetValueAtIndex( allpeople, i );
            NSString *firstName = (__bridge NSString *)(ABRecordCopyValue(ref, kABPersonFirstNameProperty));
            NSString *lastName = (__bridge NSString *)(ABRecordCopyValue(ref, kABPersonLastNameProperty));
            NSLog(@"Name:%@ %@", firstName, lastName);    }


        // The user has previously denied access
        // Send an alert telling user to change privacy setting in settings app
    }

当我在我的设备中运行此代码时，第一次在点击＆＃34之后请求许可;确定＆＃34;在权限弹出窗口中，如果我关闭应用程序＆amp;再次打开它令人惊讶地显示了所有的名字所以任何人都可以告诉我第一次和第一次的问题是什么？如何修复

Answer 1

我遇到了你的问题。实际上它会检查许可和同时它试图获取结果。

以下是简要的解决方案：

创建课程：

<强> VSContacts.h

#import <Foundation/Foundation.h>
#import <AddressBook/AddressBook.h>

@interface VSContacts : NSObject
-(BOOL)canGetContacts;
-(NSArray *)getContacts;
-(ABAddressBookRef)addressBookRef;
@property (nonatomic) ABAddressBookRef addressBook;
@end

<强> VSContacts.m

#import "VSContacts.h"

@implementation VSContacts
@synthesize addressBook = _addressBook;

-(BOOL)canGetContacts
{
    self.addressBook = [self addressBookRef];
    if (self.addressBook != NULL || self.addressBook != nil) {
        return YES;
    }

    return NO;
}

#pragma mark - Get AddressBook
-(ABAddressBookRef)addressBookRef
{
    ABAddressBookRef aBook = NULL;
    if(ABAddressBookCreateWithOptions)
    {
        CFErrorRef error;
        aBook = ABAddressBookCreateWithOptions(NULL, &error);

        __block BOOL accessGranted = NO;
        if (ABAddressBookRequestAccessWithCompletion != NULL) {
            // we're on iOS 6
            dispatch_semaphore_t sema = dispatch_semaphore_create(0);
            ABAddressBookRequestAccessWithCompletion(aBook, ^(bool granted, CFErrorRef error) {
                accessGranted = granted;
                dispatch_semaphore_signal(sema);

                dispatch_async(dispatch_get_main_queue(), ^{
                    if(granted && !error)
                    {
                        ABAddressBookRevert(aBook);
                    }
                });
            });
            dispatch_semaphore_wait(sema, DISPATCH_TIME_NOW);
            dispatch_release(sema);
        }
        else
        {
            // we're on iOS 5 or older
            accessGranted = YES;
            aBook = ABAddressBookCreate();
        }
    }
    else
    {
        aBook = ABAddressBookCreate();
    }

    return aBook ;
}

-(NSArray *)getContacts
{
    __block NSArray *contacts = nil;
    ABAddressBookRef addressBook = self.addressBook;
    if(addressBook != NULL || addressBook != nil)
    {
        CFArrayRef people = ABAddressBookCopyArrayOfAllPeople(addressBook);
        contacts = (__bridge NSArray *)people;
    }
    return contacts;
}
@end

现在：

在您的Appdelagate.h文件中：#import“VSContacts.h”
声明VSContacts * contactsHandler;
给予财产＆amp;合成它

比：

在Appdelagate.m文件中：

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
   if ([contactsHandler canGetContacts])
    {
        NSLog(@"Access Granted");
    }
    else
    {
        NSLog(@"Access Not Granted");
    }
}

完成上述操作后，请在获取联系人的页面中输入以下行：

[NSTimer scheduledTimerWithTimeInterval:2.0 target:self selector:@selector(doFetchContacts) userInfo:nil repeats:NO];

-(void)doFetchContacts
{
    CFErrorRef *error=nil;
    ABAddressBookRef addressbook=ABAddressBookCreateWithOptions(NULL, error);
    CFArrayRef allpeople=ABAddressBookCopyArrayOfAllPeople(addressbook);
    CFIndex npeople=ABAddressBookGetPersonCount( addressbook );

    for ( int i = 0; i < npeople; i++ )
    {
        ABRecordRef ref = CFArrayGetValueAtIndex( allpeople, i );
        NSString *firstName = (__bridge NSString *)(ABRecordCopyValue(ref, kABPersonFirstNameProperty));
        NSString *lastName = (__bridge NSString *)(ABRecordCopyValue(ref, kABPersonLastNameProperty));
        NSLog(@"Name:%@ %@", firstName, lastName);
    }
}

希望这会有所帮助。

Enjoyyy：）

联系人不是第一次获取

1 个答案: