Question

我使用以下查询根据日期之间的某些选择以前的股票，但是如果自动递增的id不按顺序，则以下查询失败（删除一些记录时，它有间隙），

 SELECT in_stock, price 
 FROM $tablename  
 WHERE id=(SELECT (id-1) 
           FROM $tablename 
           WHERE sale_date BETWEEN '$from_date' AND '$to_date' 
           ORDER BY entered_date ASC 
           LIMIT 1)

帮我选择之前的in_stock

Answer 1

如果ID不符合规定，您应该使用以下内容：

SELECT in_stock, price 
FROM $tablename  
WHERE entered_date=(
        SELECT MAX(entered_date) as max_date
        FROM   $tablename
        WHERE
          entered_date<(SELECT MIN(entered_date) as min_date
                        FROM $tablename 
                        WHERE
                          sale_date BETWEEN '$from_date' AND '$to_date')
      )

Answer 2

这有效，

SELECT in_stock, price 
 FROM $tablename 
 WHERE id < (SELECT min(id) 
              FROM $tablename 
              WHERE sale_date BETWEEN '$from_date' AND '$to_date') ORDER BY id DESC LIMIT 1

Answer 3

试试这个

SELECT in_stock, price 
 FROM $tablename  
 WHERE id=(SELECT (SELECT MAX(id)
                    FROM $tablename
                    WHERE id < ( SELECT MAX(id)
                    FROM $tablename )) 
           FROM $tablename 
           WHERE sale_date BETWEEN '$from_date' AND '$to_date' 
           ORDER BY entered_date ASC 
           LIMIT 1)

Answer 4

SELECT in_stock,price
 FROM $tablename  
 WHERE id=(SELECT max(id) > 1
           FROM $tablename
           WHERE sale_date BETWEEN '$from_date' AND '$to_date' 
           ORDER BY entered_date ASC 
           LIMIT 1)

选择以前的id与mysql中的where where

4 个答案: