Question

有谁能告诉我如何解决这个错误？我正在尝试创建和应用程序，当我点击切换按钮时，它将向计算机（UDP测试工具）发送一个字母或数字。 sendData（mBytes [0]）发生错误; connectSocket（＆＃34; 192.168.0.100＆＃34）;

package com.example.ledgo;

import java.io.IOException;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetSocketAddress;
import java.net.SocketException;

import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Toast;
import android.widget.ToggleButton;

public class MainActivity extends Activity {

ToggleButton tgbutton;
private byte[] mBytes = new byte[1];
private DatagramSocket mSocket;
private Toast mToast;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    tgbutton = (ToggleButton) findViewById(R.id.toggleButton1);
    tgbutton.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            if (tgbutton.isChecked()){
                mBytes[0] = (byte) (0);
                sendData(mBytes[0]);
                connectSocket("192.168.0.100");
            }
            else {
                mBytes[1] = (byte) (1);
                sendData(mBytes[1]);
                connectSocket("192.168.0.100");
            }
        }
    });
}
private void sendData(byte[] byteData){
    if(mSocket == null) return;
    int dataLen = byteData.length;
    DatagramPacket dPacket = new DatagramPacket(byteData, dataLen);
    try{
        mSocket.send(dPacket);
        try {
            Thread.sleep(25);
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }catch(IOException e){
        mToast.setText("send: " + e.toString());
        mToast.show();
    }
}

private void connectSocket(String ip){
    InetSocketAddress mAddr =  new InetSocketAddress(ip ,2390);
    try {mSocket = new DatagramSocket();}
    catch(SocketException E){
        mToast.setText("new socket: " + E.toString());
        mToast.show();
    };

    try {mSocket.connect(mAddr);}
    catch(SocketException connectE){
        mToast.setText("connect: " + connectE.toString());
        mToast.show();
        }
}

}

Answer 1

您将一个字节作为参数传递给sendData(byte[] byteData)。

尝试将代码更改为：

if (tgbutton.isChecked()){
  mBytes[0] = (byte) (0);
  sendData(mBytes);
  connectSocket("192.168.0.100");
}
else {
  mBytes[0] = (byte) (1);   //Your code actually was mBytes[1] = (byte)(1); which is invalid since you declared mBytes as an array with size 1 only.
  sendData(mBytes);
  connectSocket("192.168.0.100");
}

或简单地说，将sendData和connectSocket电话移到外面，

if (tgbutton.isChecked()){
  mBytes[0] = (byte) (0);
}
else {
  mBytes[0] = (byte) (1);
}
sendData(mBytes);
connectSocket("192.168.0.100");

我仍然认为你应该首先致电connectSocket，但这完全取决于你的实施。

Wifi编码错误

1 个答案: