Question

我有一个奇怪的错误，使用MyPhpAdmin，我添加了一行，它生成的脚本是：

INSERT INTO 'Users'.'User_Accounts'('Account_ID', 'UserName',
'Email', 'PhoneNumber', 'Password') VALUES (NULL, 'fdsfsadf',
'dfsadf', 'sdfads', 'fsdfasdfsd');

这是有效的，但是当我使用PHP PDO插入它时会出现此错误：

Table 'Users.User_Acounts' doesn't exist

嗯，是的，它确实......

PHP代码：

$hostname = "127.0.0.1";
$port     = "3306";
$database = "Users";
$username = "AccountControl";
$password = "w67hLAanWESGNJMC";

echo ">>";
$db = new PDO("mysql:host=$hostname; port=$port; dbname=$database", $username, $password);
echo ">>";
$UserName = "KiteDev";
$Email = "johndoveail.com";
$PhoneNumber = "66666";
$Password = "dfsgetagfdasg";

// Create the query
$query = "INSERT INTO User_Acounts (UserName, Email, Phon2eNumber, Password) VALUES (:name, :email, :phone, :pass )";

// Prepare statement with $stmt variable
$stmt = $db->prepare($query);
echo ">>";
// Bind parameters, (you can also remove the PDO::PARAM_INT)
$stmt->bindParam(':name', $UserName, PDO::PARAM_STR);
$stmt->bindParam(':email', $Email, PDO::PARAM_STR);
$stmt->bindParam(':phone', $PhoneNumber, PDO::PARAM_STR);
$stmt->bindParam(':pass', $Password, PDO::PARAM_STR);

// Execute the query once you're done binding all the params
$stmt->execute() or die(print_r($stmt->errorInfo(), true));
echo ">>";

关于导致这种情况的任何想法？

Answer 1

你拼错了User_Accounts。您创建的表格为User.User_Accounts，但不存在的表格为User.User_Acounts。

Answer 2

您使用一个c

编写了帐户

Table 'Users.User_Acounts' doesn't exist

Answer 3

表名为User_Accounts。在您的PHP代码中，它拼写错误为User_Acounts

将其更正为

$ query =“INSERT INTO User_Accounts（UserName，Email，Phon2eNumber，密码）VALUES（：name，：email，：phone，：pass）“;

Mysql表不存在，但它确实存在

3 个答案: