所以我可以保存图像? 图像只能以那些格式找到,而不是文件只是一个BitmapImage。
我在c#中就知道如何在C ++中创建它?
private static async Task<StorageFile> SaveAsJpeg(WriteableBitmap wb)
{
byte[] pixels;
using (var stream = wb.PixelBuffer.AsStream())
{
pixels = new byte[(uint)stream.Length];
await stream.ReadAsync(pixels, 0, pixels.Length);
}
var name = String.Format("{0}_{1:yyyy-MM-dd_HH-mm-ss}.jpg", "MyApp", DateTime.Now);
var outputFile = await KnownFolders.PicturesLibrary.CreateFileAsync(name, CreationCollisionOption.ReplaceExisting);
using (var writeStream = await outputFile.OpenAsync(FileAccessMode.ReadWrite))
{
var encoder = await BitmapEncoder.CreateAsync(BitmapEncoder.JpegEncoderId, writeStream);
encoder.SetPixelData(BitmapPixelFormat.Bgra8, BitmapAlphaMode.Premultiplied,
(uint)wb.PixelWidth, (uint)wb.PixelHeight,
96, 96, pixels);
await encoder.FlushAsync();
using (var outputStream = writeStream.GetOutputStreamAt(0))
{
await outputStream.FlushAsync();
}
}
return outputFile;
无需成为任务它可以无效而没问题......
答案 0 :(得分:0)
嗯,首先是 - 如果您首先加载BitmapImage
- 那么您可以访问源文件,因此最简单的解决方案是复制源文件。对于WriteableBitmap
- 它有点类似于C#版本,但当你开始使用类似COM的技术时,当然会稍微复杂一些。看看詹姆斯对我关于获取像素的问题的回答是否对你有所帮助:
How to get access to WriteableBitmap.PixelBuffer pixels with C++?