Question

import datetime

print datetime.datetime.now().strftime("Week of %m/%d") 
    #returns "Week of 04/18"

我想要它打印＆＃34; 4/11周到4/18＆＃34; （4/13正好提前一周）并且它需要考虑周是否在4/3结束，然后它将是＆＃34;周3/27到4/3＆＃34;

有一种简单的方法吗？

Answer 1

dateutil.relativedelta会做你想做的事：

import datetime
from dateutil.relativedelta import *

march27 = datetime.datetime(2014, 3, 27)
print (march27 + relativedelta(weeks=+1)).strftime("Week of %m/%d")
#prints "Week of 04/03"

Answer 2

您只能使用stdlib datetime模块：

from datetime import date, timedelta

now = date(2014, 4, 18)
print now.strftime('Week of %m/%d')
# -> Week of 04/18
weekbefore = now - timedelta(days=7)
print "Week of {weekbefore:%m/%d} to {now:%m/%d}".format(**vars())
# -> Week of 04/11 to 04/18

如果now = date(2014, 4, 3)，它的工作原理相同。在这种情况下，它会打印Week of 03/27 to 04/03。

在Python中显示基于当前日期的日期范围

2 个答案: