Question

我为刽子手游戏编写了代码，该游戏从文本文件中加载猜测的短语。但是当您在控制台中输入正确的字母时，它不响应。我正在寻找的是当你输入一个更新的正确信件时这个 **** * 到这个 **** a *** 。以下是我正在使用的两个课程。

import java.util.*;
import java.io.*;


public class Application {

    private  ArrayList<Pirateword> piratewords;
    private Scanner input;
    Pirateword secretWord;
    private int attempts = 10;

    public Application(){

        input=new Scanner(System.in);
        piratewords=new ArrayList<Pirateword>();
    }

    public void runApplication() throws IOException {

        load("piratewords.txt");
        hangman();
        }

    public void load(String fileName) throws IOException{
        Scanner infile =new Scanner(new InputStreamReader(new FileInputStream(fileName)));
        int num=infile.nextInt();infile.nextLine();
        for (int i=0;i<num;i++) {
            String w=infile.nextLine();
            Pirateword p=new Pirateword(w);
            piratewords.add(p);
        }
        infile.close();
    }

    public  void hangman() {
        Collections.shuffle(piratewords);
        secretWord =  piratewords.get(0);

        int len = secretWord.length(); //Store the length which will be used to see if puzzle was solved.
        char[] temp = new char[len]; //Store a temp array which will be displayed to the user
        for(int i = 0; i < temp.length; i++) //initialize the array
        {
            if(secretWord.charAt(i)!= ' '){
            temp[i] = '*';
            }
            else
            {
                temp[i] =' ';
            }
            }

        System.out.print("\n");
        System.out.print("Word to date: ");
        while (attempts <= 10 && attempts > 0)
        {
            System.out.println("\nAttempts left: " + attempts);
            System.out.print("Enter letter: ");
            String test = input.next();

            if(test.length() != 1) 
            {
                System.out.println("Please enter 1 character");
                continue;
            }

            char testChar = test.charAt(0);

            //Find matches
            int foundPos = -2;
            int foundCount = 0; //How many matches did we find
            while((foundPos = secretWord.indexOf(testChar, foundPos + 1)) != -1)
            {
                temp[foundPos] = testChar; //Update the temp array from * to the correct character
                foundCount++;
                len--; //Decrease overall counter

            }

            if(foundCount == 0)
            {
                System.out.println("Sorry, didn't find any matches for " + test);
            }
            else
            {
                System.out.println("Found " + foundCount + " matches for " + test);
            }

            //Print 
            for(int i = 0; i < temp.length; i++)
            {
                System.out.print(temp[i]);
            }
            System.out.println();

            if(len == 0)
            {
                break; //Solved!
            }

            attempts--;
        }

        if(len == 0)
        {
            System.out.println("\n---------------------------");
            System.out.println("Solved!");
        }
        else
        {
            System.out.println("\n---------------------------");
            System.out.println("Sorry you didn't find the mystery word!");
            System.out.println("It was \"" + secretWord + "\"");

    }

}

}

import java.util.*;
public class Pirateword {
    private String word;


    public Pirateword(String w) {
        word=w;
    }

    public String toString(){
        return word;

    }

    public int length(){
        return word.length();
    }



    public char charAt(int i) {
    return word.charAt(i);
    }

    public int indexOf(char guess, int i) {
        return word.indexOf(guess);
    }

}

Answer 1

您的问题在于此方法indexOf，您不使用第二个参数，即开始搜索区域的索引。

public int indexOf(char guess, int i) {
    return word.indexOf(guess, i);
}

同样foundPos应该初始化为-1。

Java刽子手项目

1 个答案: