我在b.php的表单中创建了两个提交按钮,方法是POST,并且操作到另一个页面a.php。现在我要显示,用户在页面b.php.Like中点击了哪一个 - -
<form action="a.php" method="POST">
<input type="submit" name="c" value="c">
<input type="submit" name="d" value="d">
</form>
<?php
// Some coding with "$ca"
<?php
if(isset($_POST['c']))
$ca=f;
else
$ca=g;
现在我在页面b.php中点击按钮&#34; c&#34;将重定向到页面a.php并将$ ca设置为值f。如何在页面b.php中访问$ ca的值?
答案 0 :(得分:0)
<input type="submit" id="btn1" name="btn1" />
<input type="submit" id="btn1" name="btn2" />
页 a.php ,您可以查看提交的按钮:
if (isset($_POST['btn1']))
{
echo 'button 1 was pressed';
}
else if (isset($_POST['btn2']))
{
echo 'button 2 was pressed';
}
答案 1 :(得分:0)
您可以尝试使用此代码 -
a.php页面上的-
<input type="submit" id="btn1" name="btn1" value="button1" />
<input type="submit" id="btn1" name="btn2" value="button2"/>
b.php页面上的-
if($_POST['btn1']=='button1')
{
echo "button1 has been pressed.";
}
if($_POST['btn2']=='button2')
{
echo "button2 has been pressed.";
}