Question

;With T(days,currentvalue)  
AS
(
SELECT a.days,sum(counts) as currentvalue from SUMOP A
group by days
)
Update SUMOP set sumop.currentvalue=T.currentvalue
where sumop.days=T.days

上面的查询是抛出错误。有语法错误吗？请帮忙

我在执行查询时遇到此错误：

The multi-part identifier "T.days" could not be bound.

Answer 1

您可以使用窗口函数计算每天counts的总和：

update  t
set     currentvalue = t.curval
from    (
        select  currentvalue
        ,       sum(counts) over (partition by days) as curval
        from    sumop
        ) t

See it working at SQL Fiddle.

Answer 2

在with之前添加分号，然后使用join更新。

; With T(days,currentvalue)  
AS
(
SELECT a.days,sum(counts) as currentvalue from SUMOP A
group by days
)
Update SUMOP set sumop.currentvalue=T.currentvalue
FROM SUMOP, T where sumop.days=T.days

Answer 3

您的CTE T会创建一个行集，因此您需要从联接更新。

如何逐行获取行的总和

3 个答案: