Question

我有一个游戏，在线分数存储在免费服务器上，如www.sitename.subdomain.com/globalscore.txt。

分数存储在json对象中，该对象具有json对象数组，每个对象包含播放器的名称，日期和分数。总共有20个分数，并且总是排序。

实施例

[{"scor":4290,"data":"17\/05\/14 15:30:58","nume":"MyName"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"},{"data":"-","scor":"1","nume":"Fainosag"}]

我想创建一个页面，在一个简单的表格中显示分数，例如

  <!DOCTYPE html>
<html>
<body>

<table border="1" style="width:300px">
<tr>
 <td>Position</td>
  <td>Name</td>
  <td>Score</td>        

  </tr>
 <tr>
 <td>1</td>
  <td>MyName</td>
  <td>4290</td>     

  </tr>
<tr>
 <td>2</td>
  <td>Fainosag</td>
  <td>1</td>        

  </tr>
</table>

</body>
</html>

enter image description here 当然，所有20行。我怎么能这样做？

Answer 1

可能是这样的：

我无法测试此代码。

$json = file_get_contents("http://blabla.com/myJson.txt");

$scores = json_decode($json, true);

echo "<table>";
echo "<thead><td>Position</td><td>Name</td><td>Score</td></thead>";
$i = 0;
foreach($scores as $score){
    $i++;
    echo "<tr><td>$i</td><td>".$score['nume']."</td><td>".$score['scor']."</td></tr>";
}
echo "</table>";

Answer 2

如果您正在使用PHP在服务器端使用json对象，那么：

    $content = file_get_content("www.sitename.subdomain.com/globalscore.txt");
$data = json_decode($content);
    //loop on $data and print table $rows
    foreach($data as $item) {
      print '<tr>'. '<td>' .$item->scor.'</td>' .'</tr>';
    }

Answer 3

<html>
<head>
<script> 
   $(document).ready(function(){
        // Fetch json object from server with AJAX and call updateTable(with json Object)


        function updateTable(jsonObj) {
            $(jsonObj).each(function(index, element){  
                $('#scores').append('<tr><td> '+element[0]+' </td> <td> '+element[1]+' </td> <td> '+element[2]+' </td></tr>');       
            })
        }
    });
</script>
<head>
    <body>
    .
    .
    <table id='scores' border="1">
        <tr>
            <td>Position</td>
            <td>Name</td>
            <td>Score</td>
        </tr>
    <table>  
    .
    .
    </body>

</html>

PHP - 轻松制作JSON表。

3 个答案: