PHP原始数据类型属性

Question

为什么获取任何PHP原始数据类型的属性不会触发错误或警告？

在php 5.3.28上试过这个：

$num = 1;
$str = 'hello';
$arr = array(1,2,3);
$nada = null;

$num->key1;
$str->key2;
$arr->key3;
$nada->key4;

未触发任何错误或警告。

Answer 1

您没有启用任何错误报告。当我运行你的代码时，我看到了：

PHP Notice:  Trying to get property of non-object in /home/5BSpSI/prog.php on line 8
PHP Notice:  Trying to get property of non-object in /home/5BSpSI/prog.php on line 9
PHP Notice:  Trying to get property of non-object in /home/5BSpSI/prog.php on line 10
PHP Notice:  Trying to get property of non-object in /home/5BSpSI/prog.php on line 11

尝试再次运行代码，但添加error_reporting(E_ALL);作为第一行