Question

我想在用户输入“0”时结束程序，当我使用do / while循环时工作正常但是现在我不想在输出上出现“0”...我只是希望程序在用户输入0时结束，但不将其计为输出行

这是我的输入:(每行）

1.0
0.2
10.0
20.0
0

以下是我的代码的主要部分：

main()
{
    float* fArray;
    float value;
    int counter = 0;
    int i;

    do
    {
        scanf("%f", &value);
        *(fArray + counter) = value;
        counter++;
    }
    while (value != 0);

    printf("\nThe original values are: ");
    for (i = 0; i < counter; i++)
        printf("%g ", *(fArray + i));
}

Answer 1

do
{
    scanf("%f", &value);

    if (value != 0)
    {
        *(fArray + counter) = value;
        counter++;
    }
}
while (value != 0);

Answer 2

你应该做的一些事情：我编辑并注释你的代码

#include <stdio.h>   // for I/O
#include <stdlib.h>  // for malloc

//main()         
int main(void) { // get the signature of main() right
    float* fArray;
    float value = -1;
    int N_MAX=100;  // decide on largest number of entries you will allow
    int counter = 0;
    int i;
    // allocate memory for the array!
    if((fArray = malloc(N_MAX * sizeof *fArray))==NULL) { // <<< and check that it worked
      fprintf(stderr, "error allocating memory\n");
      return -1;
    }

    do
    {
        // scan, and test for valid input:
        if(0 == scanf("%f", &value)) break;  // test that a float was read
        if (value==0) {
          break; // 0 = "end of input"
        }
        *(fArray + counter++) = value; // we only increment counter if valid value read
        if(counter >= N_MAX) {   // <<< don't run past the end of the array
          fprintf(stderr, "maximum number of entries reached\n");
          break;
        }
    }
    while (1==1);  // "infinite" loop - we break internally when break condition is met 

    // taking the next line out: moving some of the functionality into the loop
    // to correct the logic as pointed out in the comments
    // counter--; // undo the "one too far" count

    printf("\ntotal number of good values: %d\n", counter);
    printf("The original values are: ");
    for (i = 0; i < counter; i++) { // <<<< good habit to use {} even for a one liner
        printf("%g ", *(fArray + i));
    }
    printf("\n"); // <<< don't want to end without CRLF - or prompt will be at end of line
}

Answer 3

您需要分配一些内存来放置值。

即。

float fArray[1000]; // Some large enough number here

然后使用

scanf("%f", &value)); // Hopefully you get the picture and also you should check the return value
fArray[counter++] = value;

这也会增加索引counter

Answer 4

for (i = 0; i < counter-1; i++)
        printf("%g ", *(fArray + i));

Answer 5

我认为，你可以使用if语句来打印＆＃34; 0＆＃34;在输出语句中，如

for(i=0;i<counter;i++)

{if(*(fArray + i)==0)
  {}
 else{
   printf("%g ", *(fArray + i));
  }
}

Answer 6

main() {

float* fArray;
float value;
int counter = 0;
int i;
fArray = (float *) malloc(sizeof(float)*100); 

while(1){
    scanf("%f", &value);
    if(value == 0) {
          break;
    }
    *(fArray + counter ) = value;
    counter++; 
}

printf("\nThe original values are: ");
for (i = 0; i < counter; i++)
    printf("%g ", *(fArray + i));
}

从输出中删除0

6 个答案: