Question

所以，我已经有了基本卡片组，但我在打印过程中遇到了麻烦。我的教授让我们使用 eq 和 str 方法，因此我在我的代码中使用了它。我有什么错误的建议？如何更改主部分以将返回的手中的每张卡转换为字符串，然后仅将其打印出来？

import random
class Deck(object):
        """Represent a deck of 52 playing cards."""

        def __init__(self, start_shuffled):
            """Initializes a deck with 52 cards."""
            suits=["H","S","D","C"]
            ranks= list ( range(2, 11)) + ["J", "Q", "K", "A"]
            self.cards=[]
            for suit in suits:
                    for rank in ranks:
                            self.cards.append(Card(suit, rank))
            if start_shuffled:
                    random.shuffle(self.cards)
        def __str__(self):
                res = []
                for card in self.cards:
                    res.append(str(card))
                return '\n'.join(res)

        def has_card(self, card):
            return card in self.cards

        def draw_random_card(self):
            card=random.choice(self.cards)
            self.cards.remove(card)
            return card
        def draw_hand(self, num_cards):
            cards=[ ]
            for _ in range(num_cards):
                    cards.append(self.draw_random_card())
                    return cards
class Card(object) :
        def __init__(self, s , r):
            self.suit=s
            self.rank=r

        def __str__(self):
                rep = self.rank + self.suit
                return rep
        def __eq__(self, other_card):
                t1 = self.suit, self.rank
                t2 = other_card.suit, other_card.rank
                return eq(t1, t2)

def main():
        deck1=Deck(True)

        print("All the cards in the deck:")
        print(deck1.cards)
        print("Does the deck have the Queen of Hearts? True or False")
        print(deck1.has_card(Card("H", "Q")))
        card=deck1.draw_random_card()
        print("A random card from the deck:")
        print(card)
        if deck1.has_card(card):
                print("Something bad happened...")
                print(card, "Shouldn't be in the deck anymore.")
        print("A hand of six random cards:")
        print (deck1.draw_hand(6))


if __name__=="__main__":
        main()

Answer 1

你在这一行得到NameError：

return eq(t1, t2)

因为没有这样的功能eq。只需使用相等运算符。

return t1 == t2

然后，你在这一行得到了一个TypeError：

rep = self.rank + self.suit

因为有时rank是一个整数，并且您无法将整数和字符串一起添加。在连接之前将rank转换为字符串。

rep = str(self.rank) + self.suit

然后，当您打印整个套牌时，它会显示类似<__main__.Card object at 0x00000000024A19E8>的内容，因为当您在集合中打印对象时，对象不会使用__str__。为您的卡实施__repr__方法。

    def __repr__(self):
        return self.__str__()

现在你应该获得更好的输出。

All the cards in the deck:
[10H, QS, 9D, 10C, 5S, AS, 5C, 10D, AC, 9C, 3H, 3D, 
6H, JH, AD, 7D, KC, 7H, JD, 9H, 8H, 3C, 3S, 4H, 8C, 
QD, 6C, 9S, QC, 6D, JS, 7S, 5H, 10S, KH, 2C, 7C, JC, 
6S, 4D, 4S, 5D, 4C, AH, 2S, 8S, 8D, KS, 2D, KD, 2H, QH]
Does the deck have the Queen of Hearts? True or False
True
A random card from the deck:
3H
A hand of six random cards:
[3D]

Answer 2

夫妻俩：

检查draw_hand上的缩进。你永远不会把一张以上的牌放回来。
将__str__更改为__repr__。我做了这个，它开始打印出来相当正常的我。对__str__和__repr__ here
还有一些其他编译类型问题，例如直接调用__eq__，但Kevin已经解决了这些问题。

有关打印python卡牌的问题？

2 个答案: