我正在尝试编写检查数组中重复数字的代码。如果数字在同一行内重复,则应生成另一个随机数来替换该数字。这是我的类/方法,旨在实现这一目标:
import java.util.*;
public class NoRepeats
{
public static void clean(int ticks[][])
{
for(int i = 0; i < ticks.length; i++)
{
for(int j = 0; j < ticks[0].length; j++)
{
nums[j] = ticks[i][j];
}
for(int k = 0; k < nums.length; k++)
{
for(int count = k + 1; count < nums.length; count++)
{
int othNums = nums[count];
while(true)
{
if(nums[k] == othNums)
{
System.out.print("\n\n Repeat:" + nums[k] + k + " " + othNums + "\tTicket Number: " + (i+1) +"\n\n\n");
nums[k] = 1 + rndm.nextInt(48);
for(int counter = count; counter < nums.length; counter++)
{
int othNums2 = nums[count];
if(nums[k] == othNums2)
{
System.out.print("\n\n Repeat NUM2:" + nums[k] + " " + othNums2 + "\tTicket Number: " + (i+1) +"\n\n\n");
nums[k] = 1 + rndm.nextInt(48);
}
}
for(int l = 0; l < k; l++)
{
int othNums3 = nums[l];
if(nums[k] == othNums3)
{
System.out.print("\n\n RepeatNUM2: " + nums[k] + " " + othNums3 + "\tTicket Number: " + (i+1) +"\n\n\n");
nums[k] = 1 + rndm.nextInt(48);
}
}
}
else
{
break;
}
}
count++;
}
}
for(int q = 0; q < nums.length; q++)
{
ticks[i][q] = nums[q];
}
count = 0;
}
}
public static int nums[] = new int[6];
public static int count = 1;
public static Random rndm = new Random();
public static int numsMatched[] = new int[100];
}
出于某种原因,仍有比赛,我不知道为什么。谁能找到我做错了什么?
答案 0 :(得分:1)
您将count
递增两次,从而跳过条目:
for(int count = k + 1; count < nums.length; count++) //<- increment 1
{
int othNums = nums[count];
while(true)
{
//snip
}
count++; //<- increment 2
}
问题可能源于这样一个事实:你有一个静态变量,它也被称为count
,并且会被循环中定义的count
遮蔽:
public static int count = 1;
因此,要么删除第二个增量,要么重命名其中一个变量。