Question

我正在尝试使用Google的地理编码API来获取城市名称和地理位置。但我收到这个错误，不知道哪个部分出了问题。有人可以帮忙吗？

这是我的代码：

的ViewController：

- (void)searchCityGeoLocationByName:(NSString *)name
{
    [self.searchResults removeAllObjects];
    NSString *requestUrl = [[NSString stringWithFormat:@"https://maps.googleapis.com/maps/api/geocode/json?address=%@&sensor=true&key=%@", name, GOOGLE_GEOCODING_API_KEY] stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

    AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
    [manager GET:requestUrl
      parameters:nil
         success:^(AFHTTPRequestOperation *operation, id responseObject) {
             [[UIApplication sharedApplication] setNetworkActivityIndicatorVisible:NO];
             NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *)operation.response;
             if (httpResponse.statusCode == 200) {
                 dispatch_async(dispatch_get_main_queue(), ^{

                     NSMutableArray *results = [NSMutableArray array];

                     for (id response in [responseObject objectForKey:@"results"]) {
                         self.search = [[Search alloc] initWithDictionary:response];
                         [results addObject:self.search];
                     }
                     self.searchResults = [NSMutableArray arrayWithCapacity:results.count];
                     for (int i = 0; i < results.count; i++) {
                         [self.searchResults addObject:results];
                     }

                     [self.searchController.searchResultsTableView reloadData];
                 });
             }

         } failure:^(AFHTTPRequestOperation *operation, NSError *error) {
             NSLog(@"Error: %@", error);
         }];
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *CellIdentifier = @"SearchCell";
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
    if (cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
    }

    Search *search = [self.searchResults objectAtIndex:indexPath.row];
    cell.textLabel.text = search.city;

    return cell;
}

Search.h：

@interface Search : NSDictionary

- (id)initWithDictionary:(NSDictionary *)otherDictionary;

@property (nonatomic, strong) NSString *city;
@property (nonatomic, strong) NSString *lat;
@property (nonatomic, strong) NSString *lng;

@end

Search.m：

- (id)initWithDictionary:(NSDictionary *)otherDictionary
{
    self = [super init];
    if (self) {
        self.city = [otherDictionary objectForKey:@"formatted_address"];
        self.lat = [[otherDictionary valueForKeyPath:@"geometry.location"] objectForKey:@"lat"];
        self.lng = [[otherDictionary valueForKeyPath:@"geometry.location"] objectForKey:@"lng"];
    }
    return self;
}

感谢您的帮助。

Answer 1

改变这个：

for (int i = 0; i < results.count; i++) {
    [self.searchResults addObject:results];
}

为：

for (int i = 0; i < results.count; i++) {
    [self.searchResults addObject:results[i]];
}

您将数组添加到self.searchResults并尝试获取搜索对象。

Answer 2

替换

self.searchResults = [NSMutableArray arrayWithCapacity:results.count];
for (int i = 0; i < results.count; i++) {
    [self.searchResults addObject:results];
}

使用：

self.searchResults = results;

您也可以删除结果变量并直接使用self.searchResults变量。

Answer 3

当您向self.searchResults添加对象时，您每次都会添加NSMutableArray results，所以当您尝试将cellForRowAtIndexPath:分配到search时：

Search *search = [self.searchResults objectAtIndex:indexPath.row];

相反，您将返回NSMutableArray，因此在下一行中，当您尝试访问search.city时，该对象是一个数组，而不是Search对象。

您需要查看这些行是否正确：

for (int i = 0; i < results.count; i++) {
    [self.searchResults addObject:results];
}

您确定要在其中添加results吗？您希望NSMutableArray包含的NSMutableArrays是self.searchResults吗？

您可能希望用以下内容替换它：

[self.searchResults addObject:results[i]];

获取＆＃39; - [__ NSArrayM city]：无法识别的选择器发送到实例0x111c03460＆＃39;错误

3 个答案: