使用LEFT OUTER JOIN检索数据

Question

我希望能够匹配Table1中的字段和Table1中的echo数据以及Table2中的匹配字段。我试过以下但没有用。

示例：

我想按此顺序回显数据：items(Table1), category(Table1), preice(Table2), buyer(Table1)

$serchRslt = "fr732001";
$result = mysql_query("SELECT Table1.items, Table1.category, Table1.buyer, Table2.price, Table2.stocks Table2 
                       LEFT OUTER JOIN Table1 ON Table2.item = Table1.items FROM Table1 WHERE Table1.items  = '".$serchRslt."'");

while($line = mysql_fetch_array($result)) {
echo $line["items"];
echo $line["category"];
echo $line["price"];
echo $line["buyer"];
}

预期结果：fr732001 fruits 3.20 AS1

Answer 1

您的Sql语法看起来有点不稳定。尝试：

SELECT 
  Table1.items, 
  Table1.category, 
  Table1.buyer, 
  Table2.price,  
  Table2.stocks 
FROM Table1 
LEFT OUTER JOIN Table2 ON Table2.item = Table1.items
WHERE Table1.items  = $...

Answer 2

查询应该是

SELECT Table1.items, 
Table1.category, 
Table1.buyer, 
Table2.price, 
Table2.stocks 
from Table1 
LEFT OUTER JOIN Table2 
ON Table2.item = Table1.items 
WHERE Table1.items  = 'fr732001';