Question

import java.util.Scanner;

public class Assign58{

  public static void main(String[] args){
    Scanner keyboard = new Scanner(System.in);
    int numintegers, j; 
    System.out.print("Enter a positive integer: ");
    numintegers = keyboard.nextInt();
    System.out.print("Now enter " + numintegers + " integers: "); 
    int[] integers = new int[numintegers];

    for (int i=0; i < integers.length; i++){
      integers[i] = keyboard.nextInt();
      int[] reverse = new int[integers.length];

      for (i = 0, j = reverse.length - 1; i < reverse.length; i++, j--){
        reverse[j] = integers[i];
      }
    }

    System.out.print("In reverse: ");

    for (int i=0; i < integers.length; i++)
      System.out.print(integers[i] + " ");

    }
  }

因此，如果整数为3 4 6 2 9，我将如何从上面的代码中更改以下内容：

for (int i=0; i < integers.length; i++)
    System.out.print(integers[i] + " ");

使输出结果为：

9 - 2 - 6 - 4 - 3

请记住，我需要它以相反的顺序出现，我希望这些数字之间有破折号，并且在最后一个数字之后应该没有破折号。

我希望有人可以帮助我！谢谢！

Answer 1

使用此代码以相反的顺序打印数组。

int j = integers.length;        //integers is the array in which the values are stored.

for(int k=j-1; k>=0; k--)
    System.out.print(integers[k]+"-");

Answer 2

反转for循环以获得相反的顺序

for (int i=integers.length-1; i>=0 i--)
System.out.print(integers[i] + "-");

Answer 3

for (int i = integers.length; i > 0; i--) {
    System.out.print(integers[i] + " - ");
}
System.out.print(integers[0]);

Answer 4

这应该有效

for (int i=0; i < integers.length; i++){
      integers[i] = keyboard.nextInt();
      int[] reverse = new int[integers.length];

      for (i = 0, j = reverse.length - 1; i < reverse.length; i++, j--){
        reverse[i] = integers[j]+" ";
      }
    }

Answer 5

System.out.print(reverse[0]);
for (int i=1; i < integers.length; i++)
    System.out.print(" - " + reverse[i]);

其他提议的解决方案会打印一个-太多。

Answer 6

你可以从最后遍历数组

for(int i = integers.length-1; i >= 0; i--) {
    System.out.print(integers[i] + " ");
}

或者您可以使用Stack<Integer>来推送所有输入的数字，然后按相反的顺序弹出它们。

Stack<Integer> integers = new Stack<Integer>();

for (int i=0; i < numIntegers; i++){
  integers.push(keyboard.nextInt());
}

System.out.print("In reverse: ");

while(!integers.isEmpty()) {
  System.out.print(integers.pop() + " ");

}

如何使程序显示用户输入的整数的相反顺序？

6 个答案: