Question

我正在尝试提交一个表单，并且我一直收到这行代码的错误，我已经以另一种形式使用并且工作得非常好。请指导我做什么，因为我是PHP的新手，我将永远感激不尽！

$quantity=$_POST['r_quantity'];
$name=$_POST['r_firstname'];
$sname=$_POST['r_lastname'];
$tel=$_POST['r_telno'];
$email=$_POST['r_email'];
$party=$_GET['eventName'];





 if (!$name or !$sname or !$tel or !$email or !$quantity)
    {
        echo "<p>Your form is incomplete ";
        echo "<br>Please fill in details ";
        include("footlayout.html");

    }
    else

    {
    $SQL="insert into Bookings(customerFName, customerSName, customerTelNo, customerEmail, tickets) values ('".$name."','".$sname."','".$tel."','".$email."','".$quantity."')";
    $exeSQL=mysql_query($SQL);

    echo"Thank you for booking ";
    }


    $ASQL="select Quantity from PARTY where Name='$party'";
    $exeASQL=mysql_query($SQL) or die (mysql_error());
    $array=mysql_fetch_array($exeASQL);
    $quantity=$array['r_quantity'];

    if ($ticket>$quantity)
    {
    echo"Sorry There are only:" .$quantity;
    include("footlayout.html");
    exit;
    }

    echo"Thank you for booking tickets to";
    echo $party;

编辑：完成更改后，两条消息都显示“感谢您预订”和“抱歉只有：”同时，变量中的两个值都不会显示。我怎么能解决这个问题？我会把另一个'或'放进去吗？

Answer 1

替换：

{$ASQL="select Quantity from PARTY where Name='$party'";
$exeASQL=mysql_query($SQL) or die (mysql_error());
$array=mysql_fetch_array($exeASQL);
$quantity=$array['r_quantity'];

使用

$ASQL="select Quantity from PARTY where Name='$party'";
$exeASQL=mysql_query($SQL) or die (mysql_error());
$array=mysql_fetch_array($exeASQL);
$quantity=$array['r_quantity'];

（删除“$ ASQL”之前的大括号）

Answer 2

使用此：

if (!$name || !$sname || !$tel || !$email || !$quantity)
{
    echo "<p>Your form is incomplete ";
    echo "<br>Please fill in details ";
    include("footlayout.html");

}
else

{
$SQL="insert into EventBookings(customerFName, customerSName, customerTelNo, customerEmail, tickets) values ('".$name."','".$sname."','".$tel."','".$email."','".$quantity."')";
$exeSQL=mysql_query($SQL);

echo"Thank you for booking ";
}


{$ASQL="select Quantity from PARTY where Name='$party'";
$exeASQL=mysql_query($SQL) or die (mysql_error());
$array=mysql_fetch_array($exeASQL);
$quantity=$array['r_quantity'];

if ($ticket>$quantity)
{
echo "Sorry There are only:".$quantity;
include("footlayout.html");
exit;
}

echo"Thank you for booking tickets to";
echo $party;

你的错误：

echo"Sorry There are only:" $quantity;

需要使用：

echo "Sorry There are only:" . $quantity;

也许你需要使用＆＃34; ||＆＃34;而不是＆＃34;或＆＃34;。

Answer 3

请更改代码

 echo"Sorry There are only:". $quantity;

解析错误：语法错误，第32行意外的T_IF

3 个答案: