Question

我在PHP文件中生成XML数据： -

    private static function getAddressesAsXML($addressArr) {

    $addressXML = new SimpleXMLElement("<addresslist></addresslist>");
    $addressXML->addAttribute("resultcount",(int)self::get_resultcount());

    $addressIndex = 0;

    foreach ($addressArr as $addressObject) {

        $addressNode = $addressXML->addChild("address");
        $addressNode->addAttribute("id",(int)$addressIndex);

        $addressNode->addChild("pickup",htmlspecialchars($addressObject->get_pickup()));
        $addressNode->addChild("dropoff",htmlspecialchars($addressObject->get_dropoff()));
        $addressNode->addChild("BookingDateTime",$addressObject->get_bookingtime());
        $addressNode->addChild("Car",$addressObject->get_car());
        $addressNode->addChild("JbMessage",$addressObject->get_status());
        $addressNode->addChild("Zone",$addressObject->get_zone());
        $addressNode->addChild("CustomerFare",$addressObject->get_fare());
        $addressNode->addChild("PassName",$addressObject->get_passenger());
        $addressNode->addChild("CarType",$addressObject->get_cartype());
        $addressNode->addChild("Tel",$addressObject->get_tel());
        $addressNode->addChild("Comments",$addressObject->get_comments());

        $addressIndex += 1;

    }

echo $addressXML->asXML();

}

输出： -

<addresslist resultcount="2">
    <address id="0">
        <pickup>ADDRESS 1</pickup>
        <dropoff>ADDRESS 2</dropoff>
        <bookingdatetime>16/04/2014 12:03:57</bookingdatetime>
        <car></car>
        <jbmessage></jbmessage>
        <zone>NO ZONE</zone>
        <customerfare>3.5</customerfare>
        <passname>TEST</passname>
        <cartype>CAR</cartype>
        <tel>12345678912</tel>
        <comments></comments>
    </address>
</addresslist>

我需要做的是将其传递给jQuery文件，以便在jQGrid中显示信息。怎么可能实现这个目标？

Answer 1

而不是XML使用JSON。它本身支持JavaScript，更小，更快。要将PHP中的array / stdClass编码为JSON，您可以使用json_encode

将PHP值传递给jQuery

1 个答案: