Question

所以我有这个从MySQL基础生成的模型：

class Problem(models.Model):
    idproblem = models.IntegerField(db_column='idProblem', primary_key=True) 
    iduser = models.ForeignKey('User', db_column='idUser') 
    md5hash = models.CharField(db_column='md5Hash', max_length=32, blank=True)
    dateproblem = models.DateTimeField(db_column='dateProblem', blank=True, null=True)
    doneproblem = models.IntegerField(db_column='doneProblem', blank=True, null=True) 
    answerproblem = models.CharField(db_column='answerProblem', max_length=40, blank=True) 
    datedoneproblem = models.DateTimeField(db_column='dateDoneProblem', blank=True, null=True) 
    idsubproblem = models.IntegerField(db_column='idSubProblem', blank=True, null=True)
    class Meta:
        managed = False
        db_table = 'problem'

class Subproblem(models.Model):
    idproblem = models.ForeignKey(Problem, db_column='idProblem')
    idsubproblem = models.IntegerField(db_column='idSubProblem') 
    stringsubproblem = models.CharField(db_column='stringSubProblem', max_length=8, blank=True)
    iduser = models.ForeignKey('User', db_column='idUser', blank=True, null=True)
    senddateproblem = models.DateTimeField(db_column='sendDateProblem', blank=True, null=True) 
    receivedateproblem = models.DateTimeField(db_column='receiveDateProblem', blank=True, null=True) 
    idstatus = models.ForeignKey(Status, db_column='idStatus') 
    class Meta:
        managed = False
        db_table = 'subproblem'

然后我有了这个View，它负责过滤问题和SubProblem：

def pieceSender(request):
        #When I filter the Problem Model ther is no problem
    problems = Problem.objects.filter(doneproblem = False)
    problem = problems[0]

        # But when I try to do the same to the Subproblem Model the error below occours
    subproblems = Subproblem.objects.filter(idproblem = problem)
    print subproblems[0].idsubproblem

        # This is just here So that I can see the error on the Browser
    dados = {}  
    dados['status'] = 'OK'
    data_json = simplejson.dumps(dados)

     return HttpResponse(data_json)

这是提到的错误

OperationalError at /receivePiece/
     (1054, "Unknown column 'subproblem.id' in 'field list'")
     Request Method:    GET
     Request URL:   http://localhost:8000/receivePiece/
     Django Version:    1.6.2
     Exception Type:    OperationalError
     Exception Value: (1054, "Unknown column 'subproblem.id' in 'field list'")
     Exception Location:    C:\Python27\lib\site-packages\MySQLdb\connections.py in defaulterrorhandler, line 36
     Python Executable: C:\Python27\python.exe
     Python Version:    2.7.6
     Python Path:   
            ['D:\\Projetos\\sgpd',
            'C:\\Windows\\system32\\python27.zip',
            'C:\\Python27\\DLLs',
            'C:\\Python27\\lib',
            'C:\\Python27\\lib\\plat-win',
            'C:\\Python27\\lib\\lib-tk',
            'C:\\Python27',
            'C:\\Python27\\lib\\site-packages']
     Server time:   Thu, 17 Apr 2014 02:36:18 -0300

这是否会导致SubProblem Model没有PrimaryKey？

如果是这样，我如何让Django认识到这个表是Double PrimaryKey表？

任何帮助都非常感激！ = d

Answer 1

是的，这是因为你没有在子问题模型中指定一个主键，而Django正在期待一个主键。要解决此问题，请删除＆＃34; managed＆＃34;来自Meta并执行＆＃34; django-admin syncdb＆＃34;，现在一切都应该有效。

Answer 2

我认为这是因为你的模型没有主键 - Django假设你有一个名为id的pk列（自动生成）你可以查看这个应用程序：https://github.com/simone/django-compositekey - 它会允许您定义复合pk。

Django获取列表上的未知列

2 个答案: