Question

我有一个包含三列员工信息的表。第一列有雇员姓名。我想写一个谷歌应用程序脚本，它将复制预先格式化的模板表，并使用员工名称重新命名。在脚本结束时，每个员工都将拥有自己的工作表。

以下是我到目前为止的代码，我正在使用Google脚本教程中的一些功能，但我对如何继续进行操作感到茫然。编辑，我已经进一步了，这段代码工作了一次，但现在挂起了setName：

//Create new sheets for each employee in the list
function createEmployeeSheets() {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheets()[0];

  // Get the range of cells that store employee data.
  var employeeDataRange = ss.getRangeByName("EmployeeRef");

 // For every row of employee data, generate an employee object.
 var employeeObjects = getRowsData(sheet, employeeDataRange);

 for (i=0; i < employeeObjects.length; i++) {
 var EmployeeName = employeeObjects[i].name;
 ss.setActiveSheet(ss.getSheetByName("Template"));
 SpreadsheetApp.getActiveSpreadsheet().duplicateActiveSheet();
 var first = ss.getSheetByName("Copy of Template 1");
 first.setName(EmployeeName);


 }

}

Answer 1

在参观了这个Q＆amp; A后，我找到了一个更简单的方法：

function createEmployeeSheets() {
  var ss        = SpreadsheetApp.getActiveSpreadsheet();

   // Get the range of cells that store employee data.
  var employeeDataRange = ss.getRangeByName("EmployeeRef");

  var employeeObjects = employeeDataRange.getValues();

  var template = ss.getSheetByName('Template');

  for (var i=0; i < employeeObjects.length; i++) {

     // Put the sheet you want to create in a variable
     var sheet = ss.getSheetByName(employeeObjects[i]);

      // Check if the sheet you want to create already exists. If so,
      // log this and loop back. If not, create the new sheet.
        if (sheet) {
           Logger.log("Sheet " + employeeObjects[i] + "already exists");
        } else {
           template.copyTo(ss).setName(employeeObjects[i]);
           }
        }
  return;
}

Answer 2

使用copyTo()功能可以更简单。另外，请确保您拥有唯一的EmployeeNames。

所以你的代码看起来像是：

function test() {
  var ss        = SpreadsheetApp.getActiveSpreadsheet();
  var employeeObjects = [
     {"name": "Peter" },
     {"name": "Alice" },
     {"name": "Frank" }
  ]
  var template = ss.getSheetByName('Template');
  for ( var i=0; i < employeeObjects.length; i++) {
    var EmployeeName = employeeObjects[i].name;

    // get the sheets to check you are not creating a duplicate sheet 
    var sheets = ss.getSheets();
    var ok = true;

    // loop through the sheets and check a duplicate exist 
    for ( var j=0; j<sheets.length;j++ ) {
      if ( sheets[j].getName() == EmployeeName ) {
        ok = false;
        Logger.log('duplicate');
      }
    }

    if ( ok ) {
      template.copyTo(ss).setName(EmployeeName);
    } else {

      // do whatever you need to do if employee name is duplicate

    }
  }
}

Google脚本会根据列表复制和重命名工作表

2 个答案: