Question

我正在试图弄清楚如何使用AFNetworking 2.0。我正在尝试使用用户名和密码发布登录信息。

这是我目前的尝试，但由于没有发送，因此无法正常工作。

AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
NSDictionary *parameters = @{@"loginName": @"password"};
[manager POST:@"http://xxxx.com/login" parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
    NSLog(@"JSON: %@", responseObject);



    NSLog(@"Data saved");

    MainViewController *mainView = [[MainViewController alloc] initWithNibName:@"MainViewController" bundle:nil];
    mainView.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal;
    [self presentViewController: mainView animated:YES completion:nil];


} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
    NSLog(@"Error: %@", error);
    NSString *error_msg = (NSString *) error;
    [self alertStatus:error_msg :@"Sign in Failed!" :0];
}];

    }
} @catch (NSException * e) {
         NSLog(@"Exception: %@", e);
         [self alertStatus:@"Sign in Failed." :@"Error!" :0];
    }

然而，没有任何事情发生，只要继续打印出来：

2014-04-16 20:14:09.903 Slidedrawer[9279:60b] Error: Error Domain=NSCocoaErrorDomain Code=3840 "The operation couldn’t be completed. (Cocoa error 3840.)" (JSON text did not start with array or object and option to allow fragments not set.) UserInfo=0x8e78bd0 {NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.}

响应将采用JSON格式。任何人都知道我需要在代码中编辑什么或如何解决它？

JSON: {
    "_id" = 533cb1c453769a02008c2d55;
    name = dddd;
    picture = "/img/users/default.jpg";
}

如何访问上面返回的JSON，尝试将每个返回的属性拆分为字符串或整数等...

Answer 1

试试这个：

AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
NSDictionary *params = @{@"userName": username, @"password": password};
manager.responseSerializer = [AFJSONResponseSerializer serializer]; // if response JSON format
[manager POST:@"http://asd.com/login.php" parameters:params success:^(AFHTTPRequestOperation *operation, id responseObject) {
    NSLog(@"%@", responseObject);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
    NSLog(@"%@", error);
}];

要解析回复，请使用responseObject作为NSDictionary：

NSString *userName = [responseObject objectForKey:@"userName"];
NSString *password = [responseObject objectForKey:@"password"];

希望这会有所帮助.. :)

Answer 2

您可以找到答案的Send Nested JSON using AFNetworking。

错误Error Domain = NSCocoaErrorDomain Code = 3840从服务器收到无效的JSON对象。这可能是由于服务器处理您丢失的参数不当造成的。您的参数字典只有一个密钥对象loginName。

如何在iOS中发出POST请求？

2 个答案: