Question

我必须编写一个函数来检查一个值是否位于一个包含N个元素的数组中，使用for循环。我写了代码

 #include <stdio.h>
int main ()
int N[100],n,i; 
printf ("Write the value of n:");
scanf ("%d",&n);
i=0;

      printf ("Write the value of the element :");
      scanf ("%d",&v[i]);
      for (i=0,i<n,i++)
      {
          if (N[i]==n)
          }
          printf ("The value is located in the array :");



return 0;

当我编译它时，它会在printf之前说出语法错误。这是什么意思？我做错了什么？

Answer 1

基本语法问题。尝试：

#include <stdio.h>

int main(void)
{
    int N[100],n,i; 
    printf ("Write the value of n:");
    scanf ("%d",&n);
    i=0;
    printf("Write the value of the element :");
    scanf("%d", &v[i]);  /* v doesn't exist */

    /* you are looping up to n, which could be anything */
    for (i=0; i<n; i++)
    {
        /* you never populate N, so why would you expect n to be found?
        the value of any element in N is indeterminate at this point */
        if (N[i]==n)
        {
            printf ("The value is located in the array :");
        }
    }      

    return 0;
}

那就是说，你在这里遇到了逻辑问题：

v未在任何地方声明。
您永远不会填充数组（N）。
n是用户输入的值，而不是数组的上限。如果我输入101怎么办？

这些不仅仅是语法问题，您还需要修复逻辑。

C程序数组和for循环练习

1 个答案: