Question

public static void main(String[] args) {

    //Numbers
    int operand1 = 25;
    int operand2 = 6;

    //Arithmetic values
    int sum = 0;
    int difference = 0;
    int product = 0;
    int quotient = 0;
    int remainder = 0;

    //Operations
    sum = operand1 + operand2;
    difference = operand1 - operand2;
    product = operand1*operand2;
    quotient = operand1/operand2;
    remainder = operand1%operand2;

    //Output
    System.out.println("Arithmetic");
    System.out.println("============================");
    System.out.println("25 + 6 = " + sum);
    System.out.println("25 - 6 = " + difference);
    System.out.println("25 * 6 = " + product);
    System.out.println("25 / 6 = " + quotient);
    System.out.println("25 % 6 = " + remainder);

我试图找到替换＆＃34; 25 + 6＆＃34;，＆＃34; 25 - 6＆＃34;等等的方法...... （operand1＆＃34; +＆＃34; operand2＆＃34; =＆＃34; sum）因此值会根据我在oeprand1和operand2上的值而动态变化。有没有办法做到这一点？感谢

Answer 1

您执行此操作的方式与将结果变量插入字符串的方式完全相同...

System.out.println(operand1 + " + " + operand2 + " = " + sum);

如果您愿意，也可以使用printf，但必须明确插入换行符：

System.out.printf("%d + %d = %d%n", operand1, operand2, sum);

Answer 2

也许只是我，但我发现这看起来更清洁。

System.out.print(MessageFormat.format(
"Arithmetic\n" + 
"============================\n"+
"{0} + {1} = {2}\n"+
"{0} - {1} = {3}\n"+
"{0} * {1} = {4}\n"+
"{0} / {1} = {5}\n"+
"{0} % {1} = {6}\n", operand1,operand2,sum,difference,product,quotient,remainder));

MessageFormat.format提供了一种完美的替代方式来完成您所寻找的目标。

请记住有时 less 更多！为什么一遍又一遍地重复打印命令？

在println上添加多个变量

2 个答案: