Question

我正在使用Gson Library。我需要根据JsonObjects中的键对JsonObjects的JsonArray进行排序。下面给出了JsonArray

[{"AS1000":["5.1","0","false","false",null,null],"AS2000":["-","-","-","-","-","-"],"Date":"2014-03-02 08:07:00.0"},
{"AS1000":["5.0","0","false","false",null,null],"AS2000":["-","-","-","-","-","-"],"Date":"2014-03-02 17:58:00.0"},
{"AS1000":["5.0","0","false","false",null,null],"AS2000":["-","-","-","-","-","-"],"Date":"2014-03-30 14:59:00.0"},
{"AS1000":["-","-","-","-","-","-"],"AS2000":["27.0","0","true","false","30.0 - 20.0",null],"Date":"2014-03-30 06:03:00.0"},
{"AS1000":["-","-","-","-","-","-"],"AS2000":["15.0","0","false","false",null,null],"Date":"2014-03-02 02:00:00.0"},
{"AS1000":["5.0","0","false","false",null,null],"AS2000":["-","-","-","-","-","-"],"Date":"2014-03-14 20:06:00.0"},
{"AS1000":["5.0","0","false","false",null,null],"AS2000":["-","-","-","-","-","-"],"Date":"2014-03-30 07:00:00.0"},
{"AS1000":["-","-","-","-","-","-"],"AS2000":["61.0","0","false","false",null,null],"Date":"2014-03-17 19:07:59.0"}]

是否可以根据对象中的键进行排序，例如AS2000 [0]或Date？

我试过像这样的Boon

        JsonArray listLoggerDataObj=gson.fromJson(listloggerdata, JsonArray.class);
        List<JsonObject> list=new ArrayList<JsonObject>();
         for (JsonElement entry : listLoggerDataObj) {
         list.add(entry.getAsJsonObject());
         }


        sort(list,"Date"); /*list ,key used to sort*/
        System.out.println("printing sorted" +list.toString());

但它打印相同的输入。任何想法？

谢谢，

Gowrish

Answer 1

找到一个解决方案。使用Boon的jsonParser从字符串构造Json（而不是Gson的fromJson（）），然后将其转换为List，最后应用sort（），Issue Fixed。

  Object jsonObject = fromJson(listloggerdata);
  List<?> jsonDepartments = (List<?>) jsonObject;

  sort(jsonDepartments,sortBy("Date"));

  System.out.println("printing sorted" +jsonDepartments.toString());

排序后的结果是

[{"AS2000":["15.0","0","false","false",null,null],"AS1000":["-","-","-","-","-","-"],"Date":"2014-03-02 02:00:00.0"},
 {"AS2000":["-","-","-","-","-","-"],"AS1000":["5.1","0","false","false",null,null],"Date":"2014-03-02 08:07:00.0"},
 {"AS2000":["-","-","-","-","-","-"],"AS1000":["5.0","0","false","false",null,null],"Date":"2014-03-02 17:58:00.0"},
 {"AS2000":["-","-","-","-","-","-"],"AS1000":["5.0","0","false","false",null,null],"Date":"2014-03-14 20:06:00.0"},
 {"AS2000":["61.0","0","false","false",null,null],"AS1000":["-","-","-","-","-","-"],"Date":"2014-03-17 19:07:59.0"},
 {"AS2000":["27.0","0","true","false","30.0 - 20.0",null],"AS1000":["-","-","-","-","-","-"],"Date":"2014-03-30 06:03:00.0"},
 {"AS2000":["-","-","-","-","-","-"],"AS1000":["5.0","0","false","false",null,null],"Date":"2014-03-30 07:00:00.0"},
 {"AS2000":["-","-","-","-","-","-"],"AS1000":["5.0","0","false","false",null,null],"Date":"2014-03-30 14:59:00.0"}]

您甚至可以根据数组索引进行排序

 sort(jsonDepartments,sortByDesending("AS2000[0]"));

希望这可能有助于某人。

Answer 2

我也使用过Boon库，但我收到了错误＆＃34; java.lang.NoClassDefFoundError org.boon.sort.Sort＆＃34;

如果我做错了，请告诉我。

            this.list = global.getPartyPartneruserlistwithstatus().getJSONObject(0).getJSONArray("in_list");


            List<JSONObject> list1 = new ArrayList<JSONObject>();
            for (int i = 0; i < global.getPartyPartneruserlistwithstatus().getJSONObject(0).getJSONArray("in_list").length(); i++) {
                    list1.add(list.getJSONObject(i));
            }

                sort(list1,"age");

和list包含

中的JSONARRAY

[ { ＆＃34;用户名＆＃34;：＆＃34; Navdeep Singh Sandhu＆＃34;，＆＃34;家乡＆＃34;：＆＃34; chandigarh＆＃34;，＆＃34; request_id＆＃34;：＆＃34; 2＆＃34;，＆＃34; social_id＆＃34;：＆＃34; 100002878462251＆＃34;，＆＃34; social_provider＆＃34;：＆＃34; facebook＆＃34;，＆＃34;年龄＆＃34;：25 }， { ＆＃34;用户名＆＃34;：＆＃34; HarPreet Kaur＆＃34;，＆＃34;家乡＆＃34;：＆＃34; chandigarh＆＃34;，＆＃34; request_id＆＃34;：＆＃34; 4＆＃34;，＆＃34; social_id＆＃34;：＆＃34; 100002029425217＆＃34;，＆＃34; social_provider＆＃34;：＆＃34; facebook＆＃34;，＆＃34;年龄＆＃34;：23 }]

对JsonObjects Java的JsonArray进行排序

2 个答案: