Question

我在执行SQL / SQLi查询和同时上传图像时遇到问题。我可以做其中一个但不知道如何组合代码。

主要代码：

<?php
require('connect.php');

if ($_FILES["file"]["error"] > 0)
  {
  echo "Error: " . $_FILES["file"]["error"] . "<br>";
  }
else
  {
  echo "Upload: " . $_FILES["file"]["name"] . "<br>";
  echo "Type: " . $_FILES["file"]["type"] . "<br>";
  echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
  echo "Stored in: " . $_FILES["file"]["tmp_name"];
  }
$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = end($temp);
if ((($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/jpeg")
|| ($_FILES["file"]["type"] == "image/jpg")
|| ($_FILES["file"]["type"] == "image/pjpeg")
|| ($_FILES["file"]["type"] == "image/x-png")
|| ($_FILES["file"]["type"] == "image/png"))
&& ($_FILES["file"]["size"] < 20000)
&& in_array($extension, $allowedExts))
  {

  if ($_FILES["file"]["error"] > 0)
    {
    echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
    }
  else
    {
    echo "Upload: " . $_FILES["file"]["name"] . "<br>";
    echo "Type: " . $_FILES["file"]["type"] . "<br>";
    echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
    echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br>";

    if (file_exists("images/" . $_FILES["file"]["name"]))
      {
      echo $_FILES["file"]["name"] . " already exists. ";
      }
    else
      {
      move_uploaded_file($_FILES["file"]["tmp_name"],
      "images/" . $_FILES["file"]["name"]);
      echo "Stored in: " . "images/" . $_FILES["file"]["name"];
      }
    }
  }
else
  {
  echo "Invalid file";
  }
 ?>

以上代码适用于图片上传

<?php
$venuename=$_POST['venuename'];
$adress=$_POST['adress'];
$venuetype=$_POST['venuetype'];
$venuedesc=$_POST['description'];

if($venuename&&$adress&&$venuetype&&$venuedesc)
    {
    $query = mysql_query("INSERT INTO tbl_venues (venue_name,venue_description,venue_adress,venue_type) VALUES ('$venuename','$venuedesc','$adress','$venuetype')");
    header("Location: created_venue.php?");
    }
    else
    {
        echo '<div id="venuevalidation">Please complete all fields!</div>';
    }
?>

以上是插入数据的工作但是我试图将两者结合起来是不成功的，有什么建议吗？为大帖子道歉！感谢

Answer 1

全部解决，问题是括号！代码在一个部分上执行而不是移动到下一个部分。

组合图像上传和SQL查询的麻烦

1 个答案: