Question

如何在python中只获得与我的正则表达式匹配的单词？因为我尝试的所有内容也会打印出找到字符串的整行。

正则表达式如下：

\b([1-9][0-9]{1,2})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\/([0-9]{1,2})\b

匹配IP + CIDR（例如12.0.0.0/8）

我正在搜索的内容如下：

04/30","172.18.186.0/24","172.18.185.0/24","172.18.177.16/28","dwefwf-1.RI-nc_wefwfwefwefpat_intweb_fe","172.18.176.16/28","edefwfwf
t_pat_infwef_fe","172.18.178.16/28","dwefwefwef-wefwffwefwefwef_dr_efwefeb_fe","172.18.176.80/28","DSwefwfH2. 
RI-nc_rat_dr_fweweb_fe","172.18.178.48/28","172.18.177.208/28","wefwef 
wefwtfweapp_fe","172.18.176.208/28","wfwfwefwefwefH2.RI-nwefwefdr_app_fe","172.18.177.192/28","de1dfwwf-1.wefewf","172.18.176.1
92/28","

Answer 1

您应该修改regex，如下所示：

\b(([1-9][0-9]{1,2})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\/([0-9]{1,2}))\b

然后提取第一个匹配的组：\1

演示：http://repl.it/R0W/1（需要一段时间才能运行）

Answer 2

我认为你的正则表达式正常工作。如果您想获得匹配的字符串，请使用group函数。像这样：

import re

regexp = r'\b([1-9][0-9]{1,2})\.([0-9]{1,3})\.([0-9]{1,3})\.([0-9]{1,3})\/([0-9]{1,2})\b'

text = '''04/30","172.18.186.0/24","172.18.185.0/24","172.18.177.16/28","dwefwf-1.RI-nc_wefwfwefwefpat_intweb_fe","172.18.176.16/28","edefwfwf
t_pat_infwef_fe","172.18.178.16/28","dwefwefwef-wefwffwefwefwef_dr_efwefeb_fe","172.18.176.80/28","DSwefwfH2. 
RI-nc_rat_dr_fweweb_fe","172.18.178.48/28","172.18.177.208/28","wefwef 
wefwtfweapp_fe","172.18.176.208/28","wfwfwefwefwefH2.RI-nwefwefdr_app_fe","172.18.177.192/28","de1dfwwf-1.wefewf","172.18.176.1
92/28","'''

for i in re.finditer(regexp, text):
    print i.group(0)

如何获得搜索到的单词作为结果python正则表达式

2 个答案: