Question

我写了一个基于SimpleHTTPServer和SocketServer的预览函数，当我输入KeyboardInterrupt来停止服务器时，我抓住Ctrl-C异常：

#!/usr/bin/env python
# -*- coding: utf-8 -*- 
import sys 
import SimpleHTTPServer 
import SocketServer

class Reuse_TCPServer(SocketServer.TCPServer):
    timeout = 1
    allow_reuse_address = True

def preview(port=8000):
    try:
        Handler = SimpleHTTPServer.SimpleHTTPRequestHandler
        httpd = Reuse_TCPServer(("", port), Handler)
    except OSError as e:
        print("Could not listen on port {}".format(port))
        sys.exit(getattr(e, 'exitcode', 1))

    try:
        httpd.serve_forever()
    except (KeyboardInterrupt, SystemExit) as e:
        print("Shutting down server")
        httpd.socket.close()

if __name__ == "__main__":
    preview()

但大部分时间，如果我打开localhost：8000并立即（几秒钟）进入＆＃39; Ctrl-C＆＃39; ，它将首先显示该消息，然后关闭插座：

127.0.0.1 - - [16/Apr/2014 22:20:42] code 404, message File not found
127.0.0.1 - - [16/Apr/2014 22:20:42] "GET /static/css/autumn.css HTTP/1.1" 404 -
^C----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 52787)
Traceback (most recent call last):
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 295, in _handle_request_noblock
    self.process_request(request, client_address)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 321, in process_request
    self.finish_request(request, client_address)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 334, in finish_request
    self.RequestHandlerClass(request, client_address, self)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 649, in __init__
    self.handle()
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/BaseHTTPServer.py", line 340, in handle
    self.handle_one_request()
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/BaseHTTPServer.py", line 310, in handle_one_request
    self.raw_requestline = self.rfile.readline(65537)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/socket.py", line 476, in readline
    data = self._sock.recv(self._rbufsize)
KeyboardInterrupt
----------------------------------------
f^C----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 52788)
Traceback (most recent call last):
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 295, in _handle_request_noblock
    self.process_request(request, client_address)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 321, in process_request
    self.finish_request(request, client_address)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 334, in finish_request
    self.RequestHandlerClass(request, client_address, self)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 649, in __init__
    self.handle()
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/BaseHTTPServer.py", line 340, in handle
    self.handle_one_request()
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/BaseHTTPServer.py", line 310, in handle_one_request
    self.raw_requestline = self.rfile.readline(65537)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/socket.py", line 476, in readline
    data = self._sock.recv(self._rbufsize)
KeyboardInterrupt
----------------------------------------
^CShutting down server

有谁知道如何解决这个问题？

Answer 1

我的体验完全相同。我发现了Python 2.7中的一个旧错误和一个应该解决这个问题的补丁。我检查了它，补丁当然已经在SocketServer.py中了。但是，它没有解决这个问题。在任何情况下，我在这里粘贴的链接中的解释值得阅读以试图获得提示。

https://bugs.python.org/issue14574

在SocketServer中处理来自（'127.0.0.1'，xxxx）的请求时发生异常

1 个答案: